從sql結果在php中創建可點擊的鏈接

Question

我正在嘗試從php中的mysql結果可點擊鏈接中獲取結果。 我是php新手，請幫忙。

<?php mysql_connect("localhost", "root", "pass") or die(mysql_error());
mysql_select_db("Branches") or die(mysql_error());
$data = mysql_query("SELECT * FROM items order by ID desc Limit 5") or die(mysql_error());
while ($info = mysql_fetch_array($data)) {
    echo $info['title'];
    echo " <br>";
    echo $info['descr'];
    echo "<br>";
    echo "<br>";
} ?>

Answer 1

while ($info = mysql_fetch_array($data)) {
    echo '<a href="somefile.php?id='.$info['ID'].'">'.$info['title'].'</a>';
    echo " <br>";
    echo $info['descr'];
    echo "<br>";
    echo "<br>";
}

然后在somefile.php ，使用$_GET捕獲ID並顯示結果

$id = $_GET['id'];
// pull info from db based on $id
$sql = mysql_query('SELECT * FROM items WHERE ID = "'.$id.'"');
.
.
.
.

Answer 2

像這樣使用錨標簽

while ($info = mysql_fetch_array($data)) {
    echo "<a href =\"$info[title]\">".$info['title'];. "</a>";
}

Answer 3

echo '<a href="php page which you want to display on click">$info['descr']</a>'