[英]How do i convert the list of dicts having common key value pair to a new dict with keys as the common value?
[英]How to find common keys in a list of dicts and sort them by value?
我想創建一個finalDic,其中包含公用密鑰及其值的總和
myDic = [{2:1, 3:1, 5:2}, {3:4, 6:4, 2:3}, {2:5, 3:6}, ...]
首先找到通用密鑰
commonkey = [{2:1, 3:1}, {2:3, 3:4}, {2:5, 3:6}]
然后求和並按其值排序
finalDic= {3:11, 2,9}
我已經嘗試過了,甚至沒有關閉我想要的東西
import collections
myDic = [{2:1, 3:1, 5:2}, {3:4, 6:4, 2:3}, {2:5, 3:6}]
def commonKey(x):
i=0
allKeys = []
while i<len(x):
for key in x[0].keys():
allKeys.append(key)
i=i+1
commonKeys = collections.Counter(allKeys)
commonKeys = [i for i in commonKeys if commonKeys[i]>len(x)-1]
return commonKeys
print commonKey(myDic)
謝謝
這是我的處理方式:
my_dict = [{2:1, 3:1, 5:2}, {3:4, 6:4, 2:3}, {2:5, 3:6}]
# Finds the common keys
common_keys = set.intersection(*map(set, my_dict))
# Makes a new dict with only those keys and sums the values into another dict
summed_dict = {key: sum(d[key] for d in my_dict) for key in common_keys}
或者作為瘋狂的單線客:
{k: sum(d[k] for d in my_dict) for k in reduce(set.intersection, map(set, my_dict))}
只有一些指針:
實施留給OP作為練習。
l = [{2:1, 3:1, 5:2}, {3:4, 6:4, 2:3}, {2:5, 3:6}]
new_dict = {}
def unique_key_value(a,b):
return set(a).intersection(set(b))
def dict_sum(k, v):
if k not in new_dict.keys():
new_dict[k] = v
else:
new_dict[k] = new_dict[k] + v
for i in reduce(unique_key_value, l):
for k in l:
if i in k.keys():
dict_sum(i, k[i])
print new_dict
希望這可以幫助。 :)
python 3.2
from collections import defaultdict
c=defaultdict(list)
for i in myDic:
for m,n in i.items():
c[m].append(n)
new_dic={i:sum(v) for i,v in c.items()if len(v)==len(myDic)}
print(new_dic)
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