Python imaplib 獲取正文電子郵件 gmail

Question

我已經閱讀了這篇文章並編寫了這個腳本來獲取某個郵箱中標題以“$”開頭並由某個發件人發送的電子郵件正文。

import email, getpass, imaplib, os

detach_dir = "F:\PYTHONPROJECTS" # where you will save attachments
user = raw_input("Enter your GMail username --> ")
pwd = getpass.getpass("Enter your password --> ")

# connect to the gmail imap server
m = imaplib.IMAP4_SSL("imap.gmail.com")
m.login(user, pwd)

m.select("PETROLEUM") # here you a can choose a mail box like INBOX instead
# use m.list() to get all the mailboxes

resp, items = m.search(None, '(FROM "EIA_eLists@eia.gov")')
items = items[0].split() # getting the mails id

my_msg = [] # store relevant msgs here in please
msg_cnt = 0
break_ = False
for emailid in items[::-1]:
    resp, data = m.fetch(emailid, "(RFC822)")
    if ( break_ ):
        break 
    for response_part in data:
      if isinstance(response_part, tuple):
          msg = email.message_from_string(response_part[1])
          varSubject = msg['subject']
          if varSubject[0] == '$':
              msg_cnt += 1
              my_msg.append(msg)
              print msg_cnt
              print email.message_from_string(response_part[1])
              if ( msg_cnt == 5 ):
                  break_ = True 

如果我打印email.message_from_string(response_part[1]) ，我可以看到它包含第一個信息（標題，從，到，日期......），全文正文。 但是，我無法取回屍體本身。 email.message_from_string(response_part[0])打印郵件 IDS，並且email.message_from_string(response_part[2])超出范圍。 email.message_from_string(response_part[1][0])都沒有這樣做。

謝謝並恭祝安康。

更新

現在，我幾乎可以擁有正文了。 然而，它仍然被首先出現的信息聲明破壞了。 結果我得到

From nobody Tue Dec 25 11:42:58 2012

US=3D$4.030

EastCst=3D$4.036

NewEng=3D$4.205

CenAtl=3D$4.149

LwrAtl=3D$3.921

Midwst=3D$3.984

GulfCst=3D$3.945

RkyMt=3D$4.195

WCst=3D$4.187

CA=3D$4.268

我想擺脫From nobody Tue Dec 25 11:42:58 2012這是信息。 我知道我可以解析文本查找第一個相關行......我知道。

實現這樣的代碼（插入我的第一個示例）是

  if varSubject[0] == '$':
      r, d = m.fetch(emailid, "(UID BODY[TEXT])")
      msg_cnt += 1
      my_msg.append(msg)
      print email.message_from_string(d[0][1])

你有更好的方法嗎（沒有信息字符串）？？？ 更多：現在獲取日期的命令是什么？ 我知道我可以在上面適合的地方做varDate = msg['date'] ，但是如何只獲取 day-month-year ？ 謝謝

Answer 1

我設法使用 Gmail 使其工作，它提取有用的位並將它們輸出到文本文件：

import datetime
import email
import imaplib
import mailbox


EMAIL_ACCOUNT = "your@gmail.com"
PASSWORD = "your password"

mail = imaplib.IMAP4_SSL('imap.gmail.com')
mail.login(EMAIL_ACCOUNT, PASSWORD)
mail.list()
mail.select('inbox')
result, data = mail.uid('search', None, "UNSEEN") # (ALL/UNSEEN)
i = len(data[0].split())

for x in range(i):
    latest_email_uid = data[0].split()[x]
    result, email_data = mail.uid('fetch', latest_email_uid, '(RFC822)')
    # result, email_data = conn.store(num,'-FLAGS','\\Seen') 
    # this might work to set flag to seen, if it doesn't already
    raw_email = email_data[0][1]
    raw_email_string = raw_email.decode('utf-8')
    email_message = email.message_from_string(raw_email_string)

    # Header Details
    date_tuple = email.utils.parsedate_tz(email_message['Date'])
    if date_tuple:
        local_date = datetime.datetime.fromtimestamp(email.utils.mktime_tz(date_tuple))
        local_message_date = "%s" %(str(local_date.strftime("%a, %d %b %Y %H:%M:%S")))
    email_from = str(email.header.make_header(email.header.decode_header(email_message['From'])))
    email_to = str(email.header.make_header(email.header.decode_header(email_message['To'])))
    subject = str(email.header.make_header(email.header.decode_header(email_message['Subject'])))

    # Body details
    for part in email_message.walk():
        if part.get_content_type() == "text/plain":
            body = part.get_payload(decode=True)
            file_name = "email_" + str(x) + ".txt"
            output_file = open(file_name, 'w')
            output_file.write("From: %s\nTo: %s\nDate: %s\nSubject: %s\n\nBody: \n\n%s" %(email_from, email_to,local_message_date, subject, body.decode('utf-8')))
            output_file.close()
        else:
            continue

Answer 2

您可以通過執行以下任一操作來獲取正文的內容

msg.as_string()
str(msg)
repr(msg)

http://docs.python.org/2.7/library/email.message.html#email.message.Message

Answer 3

from imap_tools import MailBox

# get all attachments from INBOX and save them to files
with MailBox('imap.my.ru').login('acc', 'pwd', 'INBOX') as mailbox:
    for msg in mailbox.fetch():
        print(msg.text)
        print(msg.html)
    

這將需要外部 lib ，但要簡單得多。

https://github.com/ikvk/imap_tools

Answer 4

import datetime
import email
import imaplib
import mailbox
import re

EMAIL_ACCOUNT = "yourmail@yahoo.com"
PASSWORD = "password"
mail = imaplib.IMAP4_SSL('imap.mail.yahoo.com')
mail.login(EMAIL_ACCOUNT, PASSWORD)
mail.select('INBOX')
result, data = mail.search(None, '(FROM "Sender Email")','ALL')
result, data = mail.search(None, '(SUBJECT "Message")','ALL')
i = len(data[0].split())

if i == 1:
   latest_email_uid = data[0].split()[0]
   result, email_data = mail.uid('fetch', latest_email_uid, '(RFC822)')
   raw_email = email_data[0][1]
   raw_email_string = raw_email.decode('utf-8')
   email_message = email.message_from_string(raw_email_string)
   body = email_message.get_payload(decode=True)
   for part in email_message.walk():
        if part.get_content_type() == "text/plain":
           emailBody = part.get_payload(decode=True)
           print(emailBody)            
        else:
           continue
else:
  print('Email NOT ' + EMAIL_ACCOUNT  )