mysql 2表，從2個表中獲取結果

Question

我有2張桌子

1表=文件

      code                     | title

luLidwhSl8hmN0T6RsLaDmxAB09UZcX |這是Rar冠軍

4Xwvm1C3yTQJK7CnmxorUDI7sNSvcBK |這是JPG標題

...

2 table =命中

      page_name                                | hits

download.php？code = luLidwhSl8hmN0T6RsLaDmxAB09UZcX | 102

download.php？code = 4Xwvm1C3yTQJK7CnmxorUDI7sNSvcBK | 87

...

我的查詢是：

            include('db.inc.php');
            $query = mysql_query("SELECT t1.code, t1.title, RIGHT(t2.page_name, 31) as t2.page_name, t2.hits FROM files t1 INNER JOIN hits t2 ON t1.code= RIGHT(t2.page_name, 31) as t2.page_name ORDER by t2.hits DESC LIMIT 1, 7");

            while ($result = mysql_fetch_assoc($query)) {
                echo ' <div id="linkstyle"><strong><a href="http://localhost/edu/filesupload/download.php?code='. $result['t1.code'] . ' ">' , $result['t1.title'] , '</a></strong><br></div>';
                }

我收到這個錯誤

Warning: mysql_fetch_assoc() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\Edu\filesupload\index.php on line 104

問題出在哪兒？

Answer 1

改變這個：

$query = mysql_query("SELECT t1.code, t1.title, RIGHT(t2.page_name, 31) as t2.page_name, t2.hits FROM files t1 INNER JOIN hits t2 ON t1.code= RIGHT(t2.page_name, 31) as t2.page_name ORDER by t2.hits DESC LIMIT 1, 7");

對此：

$query = mysql_query("SELECT t1.code, t1.title, RIGHT(t2.page_name, 31) as t2.page_name, t2.hits FROM files t1 INNER JOIN hits t2 ON t1.code= RIGHT(t2.page_name, 31) as t2.page_name ORDER by t2.hits DESC LIMIT 1, 7") or die(mysql_error());

然后，這應該告訴你錯誤是什么，因為如果它沒有問題，它將不會返回false。

Answer 2

嘗試使用此查詢：

SELECT t1.code, t1.title, RIGHT(t2.page_name, 31) as page_name, t2.hits FROM files t1 INNER JOIN hits t2 ON t1.code= RIGHT(t2.page_name, 31) ORDER by t2.hits DESC LIMIT 1, 7