如何使用Java中的解析器從nmap XML String（IP，Ports）獲取信息

Question

我是編碼新手，我試圖從NMAP4j生成的XML字符串中獲取信息

<?xml version="1.0"?>
<?xml-stylesheet href="file:///usr/local/share/nmap/nmap.xsl" type="text/xsl"?>
<!-- Nmap 6.01 scan initiated Mon Jan 14 13:56:47 2013 as: /usr/local/bin/nmap -&#45;datadir /usr/local/share/nmap -T4 -oX - 192.168.1.1 -->
<nmaprun scanner="nmap" args="/usr/local/bin/nmap -&#45;datadir /usr/local/share/nmap -T4 -oX - 192.168.1.1" start="1358168207" startstr="Mon Jan 14 13:56:47 2013" version="6.01" xmloutputversion="1.04">
<scaninfo type="syn" protocol="tcp" numservices="1000" services="1,3-4,..."/>
<verbose level="0"/>
<debugging level="0"/>
<host starttime="1358168207" endtime="1358168209"><status state="up" reason="arp-response"/>
<address addr="192.168.1.1" addrtype="ipv4"/>
<address addr="xxx" addrtype="mac" vendor="yyy"/>
<hostnames>
</hostnames>
<ports><extraports state="closed" count="996">
<extrareasons reason="resets" count="996"/>
</extraports>
<port protocol="tcp" portid="21"><state state="open" reason="syn-ack" reason_ttl="64"/><service name="ftp" method="table" conf="3"/></port>
<port protocol="tcp" portid="22"><state state="open" reason="syn-ack" reason_ttl="64"/><service name="ssh" method="table" conf="3"/></port>
</ports>
<times srtt="36813" rttvar="25229" to="137729"/>
</host>
<runstats><finished time="1358168209" timestr="Mon Jan 14 13:56:49 2013" elapsed="2.48" summary="Nmap done at Mon Jan 14 13:56:49 2013; 1 IP address (1 host up) scanned in 2.48 seconds" exit="success"/><hosts up="1" down="0" total="1"/>
</runstats>
</nmaprun>

我嘗試了這段代碼：

String nmapRun = nmap4j.getOutput() ;
OnePassParser opp = new OnePassParser() ;
NMapRun nmapRun1 = opp.parse( nmapRun, OnePassParser.STRING_INPUT ) ;

但是我無法獲得具有對象並操縱這些對象以獲得所有信息的解決方案

請幫助我使用簡單的代碼示例使所有人都能理解

Answer 1

您是否要解析現有文件？ 如果是這樣的話：

OnePassParser opp = new OnePassParser() ;
NMapRun nmapRun = opp.parse( fileName, OnePassParser.FILE_NAME_INPUT ) ;