Powershell - 比較文件夾內容

Question

我有以下代碼比較兩個文件夾並輸出與每個文件夾不同的文件，有沒有辦法讓它輸出子文件夾中文件的完整文件/文件夾路徑？

干杯

 # Create varaibles to store folder paths - pass to Strings... 
 param([string]$argFolderA,[string]$argFolderB)

 # Set variables for folder
 $FolderA = Get-ChildItem -Recurse -path $argFolderA
 $FolderB = Get-ChildItem -Recurse -path $argFolderB

 # Compare the contents and output the files different within each folder. 
 Compare-Object -ReferenceObject $FolderA -DifferenceObject $FolderB >> C:\CmpOut.txt

Answer 1

使用Comapre-Object的Passthru標志，如下所示：

Compare-Object -ReferenceObject $FolderA -DifferenceObject $FolderB -Passthru | % {$_.FullName}  >> C:\CmpOut.txt

Answer 2

試試這個：

Compare-Object -ReferenceObject $FolderA -DifferenceObject $FolderB  | 
select @{n="InputObject";e={ 
     if ($_.inputobject -is [system.io.directoryinfo]) 
     {([system.io.DirectoryInfo]$_.InputObject).fullname}
      else 
      { ([system.io.FileInfo]$_.InputObject).fullname}}},SideIndicator 

Answer 3

通過ForEach {$_.InputObject.FullName}管道它。

像這樣：

Compare-Object -ReferenceObject $FolderA -DifferenceObject $FolderB | ForEach {$_.InputObject.FullName}