java Scanner類的nextLine（）問題

Question

import java.util.Scanner;

public class b {

    public static void main(String[] args){

        Scanner keyboard = new Scanner(System.in);
        String[] lines = new String[5];

        lines[0] = keyboard.nextLine();
        lines[1] = keyboard.nextLine();
        lines[2] = keyboard.nextLine();
        lines[3] = keyboard.nextLine();
        lines[4] = keyboard.nextLine();

        for (int i = 0; i < lines.length; i++) {
            System.out.println(lines[i]);
        }
    }
}

為什么上面的代碼不允許我存儲以下內容：

Hello there
How are you
My name is
Bill Gates
What is yours?

我得到的輸出是：

Hello there
How are you
My name is

Process completed.

我知道原語和nextInt（）存在問題，但我認為nextLine（）應該可以解決此問題。

Answer 1

運行此命令時，我得到以下信息：

Hello there
How are you
My name is
Bill Gates
What is yours?

如預期的那樣。

檢查您沒有運行舊版本的程序。 還可以從命令行測試您的應用程序，以排除任何IDE格式化問題。