jQuery-將一個輸入框與PHP while循環中的另一個輸入框進行比較

Question

在編寫訂單提交頁面時，我遇到了一個很大的問題，該頁面的目的是為訂單提出爭議-只要填寫兩個字段，但前提是一個字段小於另一個字段。

基本上，一個是下拉列表，另一個是“糾紛”框，查詢如下：

如果DisputesTextBox =“”和一個下拉框=“ Please Select ...”

一切都很好-啟用了提交按鈕

如果DisputesTextBox！=“”和下拉框=“請選擇...”

錯誤（反之亦然，所以如果有爭議，但dropwn =請選擇...）-提交按鈕已禁用

如果DisputesTextox！=“”和下拉框=“ Other”

一切都很好-啟用了提交按鈕

如果DisputesTextBox>發貨箱

錯誤-提交按鈕已禁用

<table>
                <thead>
                    <tr><th>Item ID</th><th>Description</th><th>Dispute Quantity</th><th>Shipped Quantity</th><th>Ordered Quantity</th><th>Reason</th></tr>
                </thead>
                <tbody>
                    <?php
                        $data = mysql_query("SELECT * FROM `artran09` WHERE `invno` = '$invoiceno'") or die(mysql_error());
                        echo "<center>";
                        $i = -1;        
                        echo "<form action=\"submitdispute.php?invno=".$invoiceno."&ordate=".$placed."\" method=\"POST\" onsubmit=\"return confirm('Are you sure you are ready to dispute your order?');\">";

                            while ($info = mysql_fetch_array($data)) {              
                                $i += 1;                                    
                                echo "<tr>"; 
                                echo "<td>".$info['item']."</td>"; 
                                echo "<td>".$info['descrip']."</td>";       

                                echo "<td><input type=\"text\" input name=".$i." onKeyPress=\"return numbersonly(this, event)\"  maxLength=\"3\"></td>"; 

                                echo "<td><input type=\"text\" value=".$info['qtyshp']." onKeyPress=\"return numbersonly(this, event)\" maxLength=\"3\" disabled=\"disabled\"></td>"; 

                                echo "<td><input type=\"text\" value=".$info['qtyord']." onKeyPress=\"return numbersonly(this, event)\" maxLength=\"3\" disabled=\"disabled\"></td>"; 

                                echo "<td><select name = \"reason$i\">";
                                echo "<option>Please Select...</option>";
                                echo "<option>Short/Not received</option>";
                                echo "<option>Damaged Goods</option>";
                                echo "<option>Product Not Ordered</option>";                    
                                echo "</select></td>";

                                echo "</tr>"; 
                            }

                    ?>
                </tbody>
            </table>
        </div>
    </div>
    <p><input type = "submit" value = "Dispute" name ="Submit">
    </form>

謝謝，希望任何人都能提供幫助！

針對Wolf /任何可以提供幫助的人進行了編輯-此處的代碼內容如下：

-我編輯的代碼-

function validateSubmit(){


   // this will loop through each row in table
   // Make sure to include jquery.js
   $('tr').each( function() {
      // Find first input
      var input1 = $(this).find('input').eq(0);
      var qty1 = input1.val();
      // Find Second input
      var input2 = $(this).find('input').eq(1);
      var qty2 = input2.val();
      // Find third input
      var input3 = $(this).find('input').eq(2);
      var qty3 = input3.val();
      // Find select box
      var selectBx = $(this).find('select');
      var selectVal = selectBx.val();
      // Add your validation code here for the inputs and select
      // Return true if all validations are correct
      // Else return false
        if(qty1 = "" && selectVal = "Please Select...") {
            return true;
            alert("You have an error somewhere, please check over your quantites.");
            break;
        }
        if (qty1 > qty2) {
            return false;
            alert("You have an error somewhere, please check over your quantites.");
            break;
        }
   });


}

Answer 1

        return true;
        alert("You have an error somewhere, please check over your quantites.");
        break;

如果調用return，則當前函數的執行將立即停止並返回該值。 這意味着在執行return語句之后什么也沒有。 alert()將不會運行，因為函數以return true結尾。