[英]MySQL row inserted but not saved?
我正在從PHP向MySQL表中插入一行,並在插入之后立即運行查詢,以獲取剛剛插入的行的鍵值,如下所示:
$stmt = $this->db->prepare("INSERT INTO user(vFirstName, vLastName, vEmail, vPassword, iSkilllevelid, vTournaments, vDays, dAddedDate, eStatus) VALUES (?,?,?,?,4,'Pick-Up','Saturday',NOW(),'Active')");
$stmt->bind_param("ssss", $firstName, $lastName, $email, $pwd);
$stmt->execute();
$stmt->close();
$stmt = $this->db->prepare('SELECT iUserId FROM user WHERE vEmail=?');
$stmt->bind_param("s", $email);
$stmt->execute();
$stmt->bind_result($iUserId);
while ($stmt->fetch()) {
break;
}
執行此代碼后, $iUserId
具有正確的自動遞增鍵值(例如1143),但是當我實際查看數據庫表時,具有該鍵的行(1143)不存在。 那怎么可能?
而不是在插入后從表中選擇,您應該使用mysqli::$insert_id
:
$stmt = $this->db->prepare('
INSERT INTO user
(vFirstName, vLastName, vEmail, vPassword, iSkilllevelid,
vTournaments, vDays, dAddedDate, eStatus)
VALUES
(?,?,?,?,4,"Pick-Up","Saturday",NOW(),"Active")
');
$stmt->bind_param('ssss', $firstName, $lastName, $email, $pwd);
$stmt->execute();
$iUserId = $this->db->insert_id;
$stmt->close();
至於為什么未從其他連接中顯示插入的數據的原因,似乎您的事務尚未提交:
$this->db->commit();
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