從下拉列表中選擇一個值將更改下一個下拉列表

Question

嗨，大家好我是Rails開發人員的紅寶石，對javascript或jquery不了解。

我有一個這樣的選擇標簽：

<select name="form[city]" id="form_city">
   <option value="">Select Office</option>
   <option value="WA - Washington PD">WA - Washington PD</option>
   <option value="CA - California PD">CA - California PD</option>
   <option value="NY - NewYork PD">NY - NewYork PD</option>
</select>

當用戶從上面的選擇標簽中選擇例如CA-California PD時 ，將在其下方的下一個選擇標簽應具有如下所示的下拉列表：

 <select name="form[cityselected]" id="form_cityselected">
   <option value="CAF">CAF</option>
   <option value="CAL">CAL</option>
   <option value="CAU">CAU</option>
   <option value="CAS">CAS</option>
</select>

因此，必須使用Javascript或JQuery函數來收集在“ form [city]”中選擇的選項並將F，L，U，S字符附加到“ form [city]”選擇標記的前兩個字符中選擇標簽->表單[cityselected]。

提前謝謝

Answer 1

檢查一下： http : //jsfiddle.net/Q8NW5/

$('#form_city').on('change', function (e) {
var val = $(':selected', $(this)).val(),
    val = val.split('-')[0],
    val = val.replace(/\s+/g, ''),
    char = ['F', 'L', 'U', 'S'],
    tpl = '<option val="{val}">{val}</option>',
    html = '';

$(char).each(function (item, value) {
    var opt = val + value;
    html += tpl.replace(/{val}/g, opt);
});

$('#form_cityselected').html(html).show();
$('#form_final_city').show();

var currCity = $('#form_cityselected option:selected').val();
setCity(currCity);

})

$('#form_cityselected').on('change', function () {
    var val = $(':selected', $(this)).val();
    setCity(val);
});

function setCity(city) {
    $('#form_final_city').val(city);
}

Answer 2

我還沒有測試過，但這是一般性的想法……這完全取決於您的確切問題。

請注意，在選擇html中添加了onSelect ...這是我更改過的唯一html

<select name="form[city]" id="form_city" onSelect="updateOtherSelect(this)">
       <option value="">Select Office</option>
       <option value="WA - Washington PD">WA - Washington PD</option>
       <option value="CA - California PD">CA - California PD</option>
       <option value="NY - NewYork PD">NY - NewYork PD</option>
    </select>

function updateOtherSelect(select){
   //grab just what happens before the first space in your option's value
   var prefix = select.options[select.selectedIndex].value.split(" ")[0];

   //go through all your second drop down values and append, based on the string FLUS (if I understood your question correctly).
   for(i=0; i< document.getItemById("form_cityselected").options.length && i < "FLUS".length; i++){
       document.getItemById("form_cityselected").options[i].value = prefix + "FLUS".charAt(i)
   }

}

Answer 3

嘗試這個

$('#form_city').change(function(){
    var cityselectedobj= $('#form_cityselected');
     cityselectedobj.empty()
    var val=$(this).val();
    var text=val.split(' ')[0];
    $('<option>').val(val + 'F').text(text+ 'F').appendTo(cityselectedobj);
    $('<option>').val(val + 'L').text(text+ 'L').appendTo(cityselectedobj);
    $('<option>').val(val + 'U').text(text+ 'U').appendTo(cityselectedobj);
    $('<option>').val(val + 'S').text(text+ 'S').appendTo(cityselectedobj);
)};

在這里擺弄

Answer 4

下面是示例：我假設您了解Jquery的基礎知識。

$("#form_city").change(function() {
     // TODO 
filltheVillagecomboBox(villageStrings);//village strings seperatedBy '|'

 });


function filltheVillagecomboBox(villagesStrings){
            if(villagesStrings !=null){
                var villagesStrings = villagesStrings.split('|');

                box.append("<option value='null'>Please select your village</option>");

                for (var i = 0, l = villagesStrings.length-1; i <l; i++){
                    var id =villagesStrings[i].substring(0,2);
                    var village=villagesStrings[i].substring(0,villagesStrings[i].length)
                    $("#form_village").append("<option value="+village+">"+village+"</option>");
            }
            }

            }