從MySQL獲取隨機行並使用PHP顯示它

Question

我試圖從我的表中選擇行引用和作者並回應它

我的目標是創建一個隨機引用生成器並顯示實際引用和作者。

我在表格中輸入了25個引號，包含3行（ID，引用，作者）

我的代碼如下，我不斷收到資源ID＃9錯誤

<?php

mysql_select_db(name of database);

$quotes = "SELECT author AND quote FROM inspirational_quotes ORDER BY RAND() LIMIT 1";

$result = mysql_query($quotes);

WHILE ($row = mysql_fetch_array($result)):
ENDWHILE; 

echo "$result";
?>

請幫忙

Answer 1

首先，我想你想要

<?php

mysql_select_db(name of database);
$quotes = "SELECT author,quote FROM inspirational_quotes ORDER BY RAND() LIMIT 1";
$result = mysql_query($quotes);

WHILE ($row = mysql_fetch_array($result)):
ENDWHILE; 

echo "$result";
?>

但我還有一個建議

預加載所有報價ID

CREATE TABLE quoteID
(
    ndx int not null auto_increment,
    id int not null,
    PRIMARY KEY (ndx)
);
INSERT INTO quoteID (id) SELECT id FROM inspirational_quotes;

現在根據quoteID表中的id選擇

SELECT B.author,B.quote FROM quoteID A INNER JOIN inspirational_quotes B
USING (id) WHERE A.ndx = (SELECT CEILING(MAX(ndx) * RAND()) FROM quoteID);

這應該可以正常擴展，因為@rnd_id的返回值來自一個在quoteID表中沒有間隙的id列表。

<?php

mysql_select_db(name of database);
$quotes = "SELECT B.author,B.quote FROM quoteID A INNER JOIN "
. "inspirational_quotes B USING (id) "
. "WHERE A.ndx = (SELECT CEILING(MAX(ndx) * RAND()) FROM quoteID)";

$result = mysql_query($quotes);

$row = mysql_fetch_array($result);

echo "$result";
?>

試試看 ！！！

Answer 2

你不能將$ result作為字符串回顯

做

    WHILE ($row = mysql_fetch_array($result)):
     echo $row['author'] . " " . $row['quote'];
ENDWHILE; 


?>

Answer 3

你沒有回應正確的變量。

echo $row['author'] . ": " . $row['quote'];

Answer 4

為什么AND剛剛逗號。

SELECT author, quote FROM inspirational_quotes ORDER BY RAND() LIMIT 1

MySQL選擇語法

Answer 5

我建議你通過PHP隨機化結果來提高性能。 例如。：

$r = mysql_query("SELECT count(*) FROM inspirational_quotes");
$d = mysql_fetch_row($r);
$rand = mt_rand(0,$d[0] - 1); 
$r = mysql_query("SELECT author,quote FROM inspirational_quotes LIMIT $rand, 1");