如果在mysql表中不存在任何結果，則回顯其他內容？

Question

有人可以幫我嗎，我試圖根據我在“權限”表中為每個用戶提供的記錄來顯示不同的圖像。 我在用 。

如果記錄不存在於表中，我想包含其他文件路徑，即

目前，如果用戶權限設置為1或0，它會顯示結果，但我想這樣做，以便在表中未找到結果時顯示默認值。

碼：

<?php if (logged_in()) { 
    $account_perms = account_perms();
    while ($perms = mysql_fetch_array($account_perms)) {
    if ($perms['privellages'] == '1')  {
        if ( mysql_num_rows( $perms ) > 0 )
              include('includes/mod_profile/mod_photos/private.php'); 
    } 
    }
    $account_perms = account_perms();
    while ($perms = mysql_fetch_array($account_perms)) {
    if ($perms['privellages'] == '0')  {
     include('includes/mod_profile/mod_photos/private2.php'); 
    } 
    } 
    $account_perms = account_perms();
    while ($perms = mysql_fetch_array($account_perms)) {
      if($perms->num_rows > 0) {
         include('includes/mod_profile/mod_photos/private2.php'); 
      } 
    } 
} ?>

Answer 1

嘗試這個：

<?
if (logged_in()) {

    $account_perms = account_perms();
    if (mysql_num_rows($account_perms)) {
        while ($perms = mysql_fetch_array($account_perms)) {
            if ($perms['privellages'] == '1') {
                if (mysql_num_rows($perms) > 0)

                    include ('includes/mod_profile/mod_photos/private.php');
            }
        }
    } else {
        echo 'No records';
    }

    $account_perms = account_perms();
    if (mysql_num_rows($account_perms)) {
        while ($perms = mysql_fetch_array($account_perms)) {
            if ($perms['privellages'] == '0') {

                include ('includes/mod_profile/mod_photos/private2.php');

            }
        }
    } else {
        echo 'No records';
    }

    $account_perms = account_perms();
    if (mysql_num_rows($account_perms)) {
        while ($perms = mysql_fetch_array($account_perms)) {
            if ($perms -> num_rows > 0) {

                include ('includes/mod_profile/mod_photos/private2.php');

            }
        }
    } else {
        echo 'No records';
    }
}
?>