[英]HQL Left Outer Join for null column in one-to-one relation
左外連接應該從左表中獲取所有數據,無論是否存在來自B表的匹配記錄,但是如果左表right_id列為空,則不能獲得記錄。
我正在解釋更多
在Data model:Order.java中,它是我的LEFT表,有一對一的關系
@OneToOne(targetEntity = OrderShippingDetail.class, optional=true, cascade = {CascadeType.ALL})
@JoinColumn(name = "SHIPPING_DETAIL_ID", referencedColumnName = "ID")
private OrderShippingDetail shippingDetail;
和HQL是:
hql = "SELECT " +
"o.id as id, " +
"o.createTime as createTime, " +
"o.customerEmailAddress as customerEmailAddress, " +
"o.customerPhoneNumber as customerPhoneNumber, " +
"o.customerNote as customerNote, " +
"o.invoicePrintedFlag as invoicePrintedFlag, " +
"shippingAddress.address.personName as shippingPersonName, " +
"shippingDetail.shippingCompany.id as shippingCompanyId, "+
"shippingDetail.shippingCompany.name as shippingCompanyName, "+
"shippingDetail.receiptNumber as shippingReceiptNumber, "+
"shippingDetail.trackingNumber as shippingTrackingNumber, "+
"shippingDetail.price as shippingPrice, "+
"o.invoiceNumber as invoiceNumber " +
"FROM Order AS o " +
"LEFT OUTER JOIN o.shippingAddress AS shippingAddress " +
"LEFT OUTER JOIN o.shippingDetail AS shippingDetail ";
但只有“SHIPPING_DETAIL_ID”不為空的記錄。 HQL有錯誤嗎? 它是通過建模SQL命令創建的,該命令是在hibernate運行時自動創建的。
我找到了這個,
HQL支持兩種形式的關聯連接:隱式和顯式。
上一節中顯示的查詢都使用顯式形式,即在from子句中顯式使用join關鍵字的位置。 這是推薦的表格。
隱式表單不使用join關鍵字。 相反,使用點符號“解除引用”關聯。 隱式連接可以出現在任何HQL子句中。 隱式連接導致生成的SQL語句中的內部聯接。
我刪除了SELECT部分中的點符號,所以我的新HQL:
hql = "SELECT " +
"o.id as id, " +
"o.createTime as createTime, " +
"o.customerEmailAddress as customerEmailAddress, " +
"o.customerPhoneNumber as customerPhoneNumber, " +
"o.customerNote as customerNote, " +
"o.invoicePrintedFlag as invoicePrintedFlag, " +
"shippingDetail, " +
"o.invoiceNumber as invoiceNumber " +
"FROM Order AS o " +
"LEFT OUTER JOIN o.shippingAddress AS shippingAddress " +
"LEFT OUTER JOIN o.shippingDetail AS shippingDetail ";
因此,它工作,它返回Order表中的所有記錄,但是,我不想選擇ShippingDetail對象中的所有列和關系。 我該怎么做才能解決這個問題?
向查詢添加另一個顯式左連接:
SELECT o.id as id,
...,
shippingCompany.id as shippingCompanyId,
shippingCompany.name as shippingCompanyName,
...
FROM Order AS o
LEFT OUTER JOIN o.shippingAddress AS shippingAddress
LEFT OUTER JOIN o.shippingDetail AS shippingDetail
LEFT OUTER JOIN shippingDetail.shippingCompany AS shippingCompany
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