[英]Hibernate: Select where in a OneToMany relation
這些是我的(縮寫)實體:
@Entity
public class User {
@OneToMany(fetch=FetchType.LAZY)
@JoinTable(name="user_items",joinColumns=@JoinColumn(name="user_id"),inverseJoinColumns=@JoinColumn(name="useritem_id"))
private Set<UserItem> items = Sets.newHashSet();
}
@Entity
@Inheritance(strategy=InheritanceType.JOINED)
public class UserItem {
@Id
@Type(type=EntityConstants.TYPE_UUID)
@Column(columnDefinition=EntityConstants.COL_UUID)
private UUID id;
}
@Entity
public class UserItemFurniture extends UserItem {
}
現在我希望通過其UUID獲取UserItemFurniture
,但UserItemFurniture
是它存在User
的items
。 這是我的嘗試:
em
.createQuery(
"SELECT f " +
"FROM UserItemFurniture f " +
"WHERE f.id = :iid " +
"AND f IN (SELECT u.items FROM User u WHERE u.id = :uid) ",
UserItemFurniture.class
)
.setParameter("uid", userId)
.setParameter("iid", itemId)
.getSingleResult();
但它會生成這個荒謬的SQL:
select useritemfu0_.id as id17_, useritemfu0_1_.item as item17_, useritemfu0_.roomNumber as roomNumber18_, useritemfu0_.x as x18_, useritemfu0_.y as y18_
from UserItemFurniture useritemfu0_ inner join UserItem useritemfu0_1_ on useritemfu0_.id=useritemfu0_1_.id
where useritemfu0_.id=? and (useritemfu0_.id in (
select .
from _User user1_, user_items items2_, UserItem useritem3_
where user1_.id=items2_.user_id and items2_.useritem_id=useritem3_.id and user1_.id=?
))
limit ?
(注意子查詢: SELECT .
)
我可以在不訴諸本機或多個查詢的情況下執行此操作嗎? 請注意, UserItem
沒有對User
的引用,這是設計UserItem
。
可以使用以下查詢:
SELECT f
FROM UserItemFurniture f
WHERE f.id = :uid AND EXISTS
(SELECT u FROM User u
WHERE u.id = :iid and f MEMBER OF u.items)
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