正则表达式或字符串解析

Question

I am trying to parse a string which has a specific pattern. An example valid string is as follows:

<STX><DATA><ETX>
<STX>A?123<ETX>
<STX><DATA><ETX>
<STX>name!xyz<ETX>
<STX>age!27y<ETX>
<STX></DATA><ETX>
<STX>A?234<ETX>
<STX><DATA><ETX>
<STX>name!abc<ETX>
<STX>age!24y<ETX>
<STX></DATA><ETX>
<STX>A?345<ETX>
<STX><DATA><ETX>
<STX>name!bac<ETX>
<STX>age!22y<ETX>
<STX></DATA><ETX>
<STX>OK<ETX>
<STX></DATA><ETX>

this data is sent by device. All I need is to parse this string with id:123 name:xyz, age 27y.

I am trying to use this regex:

final Pattern regex = Pattern.compile("(.*?)", Pattern.DOTALL);

this does output the required data :

<ETX>
<STX>A?123<ETX>
<STX><DATA><ETX>
<STX>name!xyz<ETX>
<STX>age!27y<ETX>
<STX>

How can I loop the string recursively to copy all into list of string. I am trying to loop over and delete the extracted pattern but it doesn't delete.

    final Pattern regex = Pattern.compile("<DATA>(.*?)</DATA>", Pattern.DOTALL);// Q?(.*?)
    final StringBuffer buff = new StringBuffer(frame);
    final Matcher matcher = regex.matcher(buff);
    while (matcher.find())
        {
            final String dataElements = matcher.group();
            System.out.println("Data:" + dataElements);
        }
    }

Are there any beter ways to do this.

This is the output I am currently getting:

Data:<DATA><ETX><STX>A?123<ETX><STX><DATA><ETX><STX>name!xyz<ETX><STX>age!27y<ETX><STX>   </DATA>
Data:<DATA><ETX><STX>name!abc<ETX><STX>age!24y<ETX><STX></DATA>
Data:<DATA><ETX><STX>name!bac<ETX><STX>age!22y<ETX><STX></DATA>

I am missing the A?234 and A?345 in the next two matches.

Answer 1

I really dont know what exactly you want to achieve by this but if you want to remove the occurances of that pattern this line:

buff.toString().replace(dataElements, "")

doesn't look good. you are just editing the string representation of that buff. You have to again replace the edited version back into the buff (after casting).

Answer 2

使用此正则表达式解决了我的问题：

<STX>(A*)(.*?)<DATA>(.*?)</DATA>