在Java中使用Regex解析字符串

Question

I have a String which is formatted as such

[dgdds,dfse][fsefsf,sefs][fsfs,fsef]

How would I use Regex to quickly parse this to return an ArrayList with each value containing one "entry" as such?

ArrayList <String>:

0(String): [dgdds,dfse]

1(String): [fsefsf,sefs]

2(String): [fsfs,fsef]

Really stuck with this, any help would be great.

Answer 1

How about

String myData = "[dgdds,dfse][fsefsf,sefs][fsfs,fsef]";
List<String> list = new ArrayList<>(Arrays.asList(myData
        .split("(?<=\\])")));

for (String s : list)
    System.out.println(s);

Output:

[dgdds,dfse]
[fsefsf,sefs]
[fsfs,fsef]

This regex will use look behind mechanism to split on each place after ] .

Answer 2

You should try this regex :
Pattern pattern = Pattern.compile("\\\\[\\\\w*,\\\\w*\\\\]");

Answer 3

Old, easy, awesome way :)

String s = "[dgdds,dfse][fsefsf,sefs][fsfs,fsef]";
        String[] token = s.split("]");
        for (String string : token) {
            System.out.println(string + "]");
        }

Answer 4

You may need to do it in two passes:

(1) Split out by the brackets if it's just a 1D array (not clear in the question):

String s = "[dgdds,dfse][fsefsf,sefs][fsfs,fsef]";
String[] sArray = s.split("\\[|\\]\\[|\\]");

(2) Split by the commas if you want to also divide, say "dgdds,dfse"

sArray[i].split(",");

Answer 5

You can use simple \\[.*?\\] regex, which means: match a string starting with [ , later zero or more characters (but as short as possible, not greedly, that's why the ? in .*? ), ending with ] .

This works, you can test it on Ideone :

List<String> result = new ArrayList<String>();
String input = "[dgdds,dfse][fsefsf,sefs][fsfs,fsef]";
Pattern pattern = Pattern.compile("\\[.*?\\]");
Matcher matcher = pattern.matcher(input);
while (matcher.find()) 
{
    result.add(matcher.group());
}
System.out.println(result);

Output:

[[dgdds,dfse], [fsefsf,sefs], [fsfs,fsef]]

Answer 6

We can use split(regex) function directly by escaping "]" : "\\\\]" and then use it as the regex for pattern matching:

String str = "[dgdds,dfse][fsefsf,sefs][fsfs,fsef]";
     String bal[] = str.split("\\]");

     ArrayList<String>finalList = new ArrayList<>();

     for(String s:bal)
     {
         finalList.add(s+"]");
     }
     System.out.println(finalList);

Answer 7

如果][之间没有任何内容，则使用此(?:(?<=\\])|^)(?=\\[)拆分可能有效