[英]Regex in Java - parsing a string array
I have a string array like this:我有一个这样的字符串数组:
String tweetString = ExudeData.getInstance().filterStoppingsKeepDuplicates(tweets.text);
// get array of words and split
String[] wordArray = tweetString.split(" ");
After I split the array, I print the following:拆分数组后,我打印以下内容:
System.out.println(Arrays.toString(wordArray));
And the output I get is:我得到的输出是:
[new, single, fallin, dropping, days, artwork, hueshq, production, iseedaviddrums, amp, bigearl7, mix, reallygoldsmith, https, , , t, co, dk5xl4cicm, https, , , t, co, rvqkum0dk7]
What I want is to remove all the instances of commas, https, and single letters like 't' (after using split
method above).我想要的是删除所有的逗号、https 和像 't' 这样的单个字母的实例(在使用上面的split
方法之后)。 So I want to end up with this:所以我想以这样的方式结束:
[new, single, fallin, dropping, days, artwork, hueshq, production, iseedaviddrums, amp, bigearl7, mix, reallygoldsmith, co, dk5xl4cicm, https, co, rvqkum0dk7]
I've tried doing replaceAll like this:我试过像这样做 replaceAll:
String sanitizedString = wordArray.replaceAll("\\s+", " ").replaceAll(",+", ",");
But that just gave me the same initial output with no changes.但这只是给了我相同的初始输出,没有任何变化。 Any ideas?有任何想法吗?
If you are using Java 8如果您使用的是 Java 8
String[] result = Arrays.stream(tweetString.split("\\s+"))
.filter(s -> !s.isEmpty())
.toArray(String[]::new);
What I want is to remove all the instances of commas, https, and single letters like 't'我想要的是删除逗号、https 和单个字母(如“t”)的所有实例
In this case you can make multiple filters like @Andronicus do or with matches and some regex like so :在这种情况下,您可以制作多个过滤器,例如@Andronicus 或使用匹配项和一些正则表达式,如下所示:
String[] result = Arrays.stream(tweetString.split("\\s+"))
.filter(s -> !s.matches("https|.|\\s+"))
.toArray(String[]::new);
You can do something like this:你可以这样做:
String[] filtered = Arrays
.stream(tweetString.split("[ ,]"))
.filter(str -> str.length() > 1)
.filter(str -> !str.equals("http"))
Based on my comment here is quick solution.根据我的评论,这里是快速解决方案。 (Enhance the regex with all your keywords) (使用所有关键字增强正则表达式)
private static void replaceFromRegex(final String text ) {
String result = text.replaceAll("https($|\\s)| (?<!\\S)[^ ](?!\\S)","");
System.out.println(result);
}
and then test然后测试
public static void main(String []args) throws Exception{
replaceFromRegex("new single fallin dropping, , https");
}
Note: This is just sample and you will have to enhance regex to consider starting word (eg string starting with https and then space, etc)注意:这只是示例,您必须增强正则表达式以考虑起始词(例如以 https 开头的字符串,然后是空格等)
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