将十进制数转换为年份和月份SQL * Plus

Question

I am trying to get an age in years and months from a given DOB. Right now, my code looks like this:

COLUMN name FORMAT A25
SELECT sNo, fName||CHR(13)||lName Name, sex, TRUNC((CURRENT_DATE - dob) / 365.24, 1) Age
FROM Staff
WHERE position IN ('Manager', 'Secretary')
ORDER BY age DESC;

And it gives me Age outputs in decimal numbers (such as 58.6) which I understand, but I am needing to convert that .6 into a month somehow.

I am thinking that my method of doing this conversion isn't the most efficient, but I have been searching for hours for a solution, but to no avail. I've seen DATEDIFF, but I keep getting an invalid identifier error when trying to use it.

Any ideas?

Answer 1

How about something like this:

SELECT sNo, fName||CHR(13)||lName Name, sex, 
  TRUNC((CURRENT_DATE - dob) / 365.24, 1) Age,
  TRUNC(MONTHS_BETWEEN(CURRENT_DATE, dob) / 12) YEARS,
  MOD(TRUNC(MONTHS_BETWEEN(CURRENT_DATE, dob)), 12) MONTHS
FROM Staff
WHERE position IN ('Manager', 'Secretary')
ORDER BY age DESC;

And here is the SQL Fiddle .

And this should get you the days as well: http://sqlfiddle.com/#!4/f3a57/4

SELECT sNo, fName||CHR(13)||lName Name, sex, 
  TRUNC((CURRENT_DATE - dob) / 365.24, 1) Age,
  TRUNC (MONTHS_BETWEEN (CURRENT_DATE, dob) / 12) YEARS,
  MOD (TRUNC (MONTHS_BETWEEN (CURRENT_DATE, dob)), 12) MONTHS,
  TO_DATE (CURRENT_DATE) - 
      ADD_MONTHS (dob,TRUNC (MONTHS_BETWEEN (CURRENT_DATE, dob))) DAYS
FROM Staff
WHERE position IN ('Manager', 'Secretary')
ORDER BY age DESC;

Good luck.

Answer 2

SELECT sNo, fName||CHR(13)||lName Name, sex, 
 DATEDIFF(year, dob, Current_Date) - 1 + ' years & ' + dbo.FullMonthSeperation(CURRENT_DATE, dob) + ' months.' AS 'Age'
FROM Staff
WHERE position IN ('Manager', 'Secretary')
ORDER BY age DESC;

I borrowed the function from Calculating number of full months between two dates in SQL as you've got to both consider negative and positive values depending on the time of the year... I'm sure there's a better way to do the months also, the year should be optimal.

Hope this works in SQL Plus! Same concept though.