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如何实现扩展类的构造函数

[英]How to implement constructor for extended class

This works: 这有效:

class ABean implements A {
  protected String field1;
  ...
  protected String fieldn;

  public String getField1() {
   return field1;
  }
  ...
}


class BBean extends ABean {
  public BBean(A a) {
    super();
    this.field1=a.getField1();
    ...
    this.fieldn=a.getFieldn();
  }
}

But writing this constructor B(A a) is cumbersome, not really practical, and error prone because if I add or remove fields in A , then I need to modify that constructor and may sometimes forget to initialize some of the fields present in A . 但是编写此构造函数B(A a)很麻烦,不实际,并且容易出错,因为如果我在A添加或删除字段,那么我需要修改该构造函数,有时可能会忘记初始化A存在的某些字段。

I suppose I could implement clone for ABean, but that would have similar issues (because the clone implementation would need to be updated when I add/remove fields) and that would also not allow me to have a BBean(A a) constructor; 我想我可以为ABean实现克隆,但是会有类似的问题(因为在添加/删除字段时需要更新克隆的实现),并且也不允许我拥有BBean(A a)构造函数; only a BBean(ABean a) constructor unless I make the clone() part of the interface also. 除非我也将clone() BBean(ABean a)接口的一部分,否则只能是BBean(ABean a)构造函数。

So... is there a cleaner, better way of implementing BBean(A a) ? 那么... 有没有更清洁,更好的方法来实现BBean(A a)

Instead of using inheritance, try using composition. 而不是使用继承,请尝试使用组合。 That is, instead of BBean extends ABean , make your BBean have a constructor BBean(ABean a) . 也就是说,不是让BBean extends ABean ,而是让您的BBean具有构造函数BBean(ABean a) That way you've shielded yourself from all the details of how to construct a new ABean in BBean 's code. 这样,您就避免了如何在BBean的代码中构造新的ABean所有细节。

What about implementing an "A"-constructor (copy-constructor) on your ABean as follows: 如何在ABean上实现“ A”构造函数(复制构造函数),如下所示:

class ABean implements A {
    protected String field1;
    ...
    protected String fieldn;

    public String getField1() {
        return field1;
    }
    ...
    public ABean(A other) {
        this.field1=other.getField1();
        ...
        this.fieldn=other.getFieldn();
    }
}


class BBean extends ABean {
    public BBean(A a) {
        super(a);
    }
}

This way, your "copy-constructor" mapping for A's is all in your ABean. 这样,您的A的“复制构造函数”映射就位于您的ABean中。

you can use reflection: 您可以使用反射:

class A {}

class B {
public B(A a) {
    String methodName = null;
    try {
        Field[] fields = a.getClass().getDeclaredFields();
        for (Field field : fields) {
            methodName = field.getName().substring(0, 1).toUpperCase()
                    + field.getName()
                            .substring(1, field.getName().length());
            field.get(a);
            this.getClass().getMethod("set" + methodName, field.getClass()).invoke(a, field.get(a));
        }
    } catch (Exception e) {
        e.printStackTrace();
    }
}

} }

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