[英]How to Instantiate a class with the class type, using constructor of extended class with method 'getDeclaredConstructor', in Android Studio
public class MainMenu extends GameMenu{
Table table;
Skin skin;
public MainMenu(){super();};
protected void loadWidgets(){
skin.add("playButton", com.mygdx.game.LIBGDXwrapper.gameGUI.widgets.MainMenuWidgets.loadPlayButton(table));
table.row();
skin.add("hightScoreButton", com.mygdx.game.LIBGDXwrapper.gameGUI.widgets.MainMenuWidgets.loadHighScoreButton(table));
//table.row();
}
protected void loadInputlisteners(){
skin.get("playButton", Button.class);
}
@Override
public String toString(){
return "Menu";
}
}
public abstract class GameMenu extends Stage{
private Settings gameSettings;
//public GameMenu(Settings gameSettings){
// this.gameSettings = gameSettings;
//}
public GameMenu(){};
protected abstract void loadWidgets();
protected abstract void loadInputlisteners();
}
private static enum GameMenus {MainMenu(MainMenu.class);
private final Class<? extends GameMenu> menuType;
GameMenus(Class<? extends GameMenu> menuType){
this.menuType = menuType;
}
public Class<? extends GameMenu> createInstance(Settings gameSettings){
GameMenu gui = menuType.getDeclaredConstructor().newInstance();
}
};
I have been trying to make this work for hours now, is it possible to get an instance of a derived class from 'GameMenu' with the class type 'Class< ? 我一直在尝试使它工作数小时,是否有可能从'GameMenu'中获得类类型为'Class <的派生类的实例? extends GameMenu>'?
扩展GameMenu>'? Note that all derived classes of 'GameMenu' have a constructor that with one argument 'Settings'.
请注意,“ GameMenu”的所有派生类都有一个带有一个参数“ Settings”的构造函数。
I'm getting NoSuchMethodExpection from the method 'getDeclaredConstructor'. 我从方法'getDeclaredConstructor'中获取NoSuchMethodExpection。
I would be very grateful if anyone could help me. 如果有人可以帮助我,我将不胜感激。
So you said: 所以你说:
Note that all derived classes of 'GameMenu' have a constructor that with one argument 'Settings'.
请注意,“ GameMenu”的所有派生类都有一个带有一个参数“ Settings”的构造函数。
But you use: 但是您使用:
menuType.getDeclaredConstructor()
If you take a look at the javadoc , you will see that getDeclaredConstructor()
returns the "no args" constructor if any. 如果看一下javadoc ,您将看到
getDeclaredConstructor()
返回“ no args”构造函数(如果有)。 You probably want to specify the constructor argument type: 您可能要指定构造函数参数类型:
menuType.getDeclaredConstructor(Settings.class)
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