[英]Regular Expression that might contain 8 or 9 numbers - how to do?
I use this regular expression to validate brazilian cellphones: 我使用此正则表达式来验证巴西手机:
/^(\([0-9]{2}\))\s([9]{1})?([0-9]{4})-([0-9]{4})$/
Output: (31) 8876-3234
VALID 输出: (31) 8876-3234
有效
But Sao Paulo state has 9 digits cellphones: 但是圣保罗州有9位数字的手机:
Output SP : (31) 98876-3234
输出SP : (31) 98876-3234
Current regex needs tweak to accept that as valid too, any tips on what should I change in it? 当前的正则表达式也需要进行调整,以使其也同样有效,关于该如何更改的任何提示?
You can use {m,n}
quantifier to create a range: 您可以使用{m,n}
量词来创建范围:
/^(\([0-9]{2}\))\s([0-9]{4,5})-([0-9]{4})$/
Though your regex seems to be fine, as it has an optional 9
to match before the 4 digits. 尽管您的正则表达式看起来不错,但它有一个可选的9
可以匹配4位数字。 But if there is any possibility that there can be anything else than 9
there, then you can use this regex. 但是,如果存在9
以外的任何其他可能性,则可以使用此正则表达式。
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