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斯卡拉,游戏,期货:结合多个期货的结果

[英]scala, play, futures: combining results from multiple futures

I am using: 我在用:

  • Scala 2.10 斯卡拉2.10
  • Play 2.1 玩2.1

Currently, I am using the Future class from scala.concurrent._ , but I'm open to trying another API. 目前,我正在使用scala.concurrent._Future类,但我愿意尝试另一个API。

I am having trouble combining the results of multiple futures into a single List[(String, String)]. 我无法将多个期货的结果合并到一个List [(String,String)]中。

The following Controller method successfully returns the results of a single Future to an HTML template: 以下Controller方法成功将单个Future的结果返回到HTML模板:

  def test = Action { implicit request =>
    queryForm.bindFromRequest.fold(
      formWithErrors => Ok("Error!"),
      query => {
        Async { 
          getSearchResponse(query, 0).map { response =>
            Ok(views.html.form(queryForm,
              getAuthors(response.body, List[(String, String)]())))
          }
        }
      })
  }

The method getSearchResult(String, Int) performs a web service API call and returns a Future[play.api.libs.ws.Response]. 方法getSearchResult(String, Int)执行Web服务API调用并返回Future [play.api.libs.ws.Response]。 The method getAuthors(String, List[(String, String)]) returns a List[(String, String)] to the HTML template. 方法getAuthors(String, List[(String, String)])将List [(String,String)]返回给HTML模板。

Now, I am trying to call getSearchResult(String, Int) in a for loop to get several Response bodies. 现在,我试图在for循环中调用getSearchResult(String, Int)来获取几个Response主体。 The following should give an idea of what I'm trying to do, but I get a compile-time error: 以下内容应该说明我正在尝试做什么,但是我得到了一个编译时错误:

  def test = Action { implicit request =>
    queryForm.bindFromRequest.fold(
      formWithErrors => Ok("Error!"),
      query => {
        Async {
          val authors = for (i <- 0 to 100; if i % 10 == 0) yield {
            getSearchResponse(query, i)
          }.map { response =>
            getAuthors(response.body, List[(String, String)]())
          }

          Ok(views.html.form(queryForm, authors))
        }
      })
  }

type mismatch; 类型不匹配; found : scala.collection.immutable.IndexedSeq[scala.concurrent.Future[List[(String, String)]]] required: List[(String, String)] found:scala.collection.immutable.IndexedSeq [scala.concurrent.Future [List [(String,String)]]] required:List [(String,String)]

How can I map the responses of several Future objects to a single Result ? 如何将多个Future对象的响应映射到单个Result

Create a Future parametrized by a List or other Collection of the Result type. 创建由List或Result类型的其他Collection参数化的Future。

From here : 这里

In Play 1 you can do this: 在Play 1中,您可以这样做:

    F.Promise<List<WS.HttpResponse>> promises = F.Promise.waitAll(remoteCall1, remoteCall2, remoteCall3);

    // where remoteCall1..3 are promises

    List<WS.HttpResponse> httpResponses = await(promises); // request gets suspended here

In Play 2 less direct: 在Play 2中不那么直接:

    val httpResponses = for {
  result1 <- remoteCall1
  result2 <-  remoteCall2
} yield List(result1, result2)

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