简体   繁体   English

使用多个Scala期货

[英]Working with multiple Scala Futures

I've more than one Future . 我有不止一个Future

val actor1 : Future[ActorRef] = createActorA()
val actor2 : Future[ActorRef] = createActorB() 
...
...
...

Now I need to extract the ActorRef s from all these futures so that I can use them to create a Router . 现在我需要从所有这些期货中提取ActorRef ,以便我可以使用它们来创建Router

val routees = Vector[ActorRef](actor1, actor2, .....)
val router = system.actorOf(Props.empty.withRouter(
  RoundRobinRouter(routees = routees)))

I can call Await on each of these Future s to get the ActorRef . 我可以打电话给Await在这些的Future s到获得ActorRef Is there is a better way ? 有更好的方法吗?

Use Future.sequence with foreach : foreach使用Future.sequence

Future.sequence(Vector(
  createActorA(),
  createActorB() // and so on
)) foreach { routees =>
  val router = system.actorOf(Props.empty.withRouter(
    RoundRobinRouter(routees = routees)))
  // do something with router
}

Future.sequence takes a collection of futures and returns a future holding a collection with the result of those futures, in this case it returns Future[Vector[ActorRef]] . Future.sequence收集期货的集合并返回一个包含这些期货结果的集合的未来,在这种情况下它返回Future[Vector[ActorRef]] We then invoke foreach on this future to attach a handler to the completion of this future. 然后我们在这个未来调用foreach来附加一个处理程序来完成这个未来。 This gives us access to the collection (the routees ) and we create the needed router. 这使我们可以访问集合( routees ),并创建所需的路由器。 We can continue to do further processing in the function passed to foreach. 我们可以继续在传递给foreach的函数中进行进一步处理。

You may use for-comprehension. 你可以使用for-understanding。

val actors: Future[(ActorRef, ActorRef)] = for {
  a <- createActorA()
  b <- createActorB()
} yield (a -> b)
// Await on actors

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM