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在给定用户名时,从无序的MySql数据库中获取基于分数的排名

[英]Get a rank, based on score, from an unordered MySql Database when given a Username

Okay so I have a table that has the following 好的,所以我有一张表有以下内容

KEY   username   password   score  

The above columns are not in any specific order. 以上列没有任何特定顺序。

I want to send my Database a username and have it send me back what rank that user name is based on its score. 我想向我的数据库发送一个用户名,让它根据其得分将该用户名的等级发回给我。 So for example if I had 10 people in there and the 3rd person in has the highest score. 例如,如果我在那里有10个人,那么第3个人的得分最高。 When I pass the 3rd persons username in I want it to send back 1. 当我通过第三人的用户名时,我希望它发回1。

Is this possible? 这可能吗?

I have been trying things like this 我一直在尝试这样的事情

$result = mysql_query("SELECT * FROM tablename where username='$username' ORDER BY score DESC");

but it doesnt seem to give me the row number 但它似乎没有给我行号

This will handle ranks that have the same score. 这将处理具有相同分数的排名。

SELECT  d.*, c.ranks
FROM
        (
          SELECT    Score, @rank:=@rank+1 Ranks
          FROM
                  (
                      SELECT  DISTINCT Score 
                      FROM    tableName a
                      ORDER   BY score DESC
                  ) t, (SELECT @rank:= 0) r
        ) c 
        INNER JOIN tableName d
            ON c.score = d.score
// WHERE   d.username = 'Helen'

for example 例如

KEY     username    password    score   Ranks
1       Anna        123         5       3
2       Bobby       345         6       2
3       Helen       678         6       2
4       Jon         567         2       4
5       Arthur      ddd         8       1

for better performance, add an INDEX on column Score , 为了获得更好的性能,请在列Score上添加INDEX

ALTER TABLE tableName ADD INDEX (Score)
SELECT 
    (SELECT COUNT(*)+1 FROM tablename WHERE score > t.score) as rank,
    * 
FROM
     tablename t
where 
     username='$username'

The ORDER BY in your query is useless since you're only returning one row. 查询中的ORDER BY是无用的,因为您只返回一行。

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