根据总分和时间获取用户排名位置

Question

I want to get the user rank position based on the total score and average time. However, the query I am using gives the wrong position number.

$myId = TotalScore::where('user_id', $user_id)->first();
$position = TotalScore::where('ts', '>=', $myId->ts)
    ->where('avg_times_taken', '>=', $myId->avg_times_taken)->count();

Table structure

Let's say I want to know my rank position. The query needs to compare my total score (ts) and the average time taken ( avg_times_taken ) and display my position. If two users get the same score, the one with the lower average time ranked better.

Answer 1

From the above comments, it is clear that total score and the average time taken are inversely related. Ie the ratio between the total_score and average_time_taken, should give us some value that we'll now use to position or order our records. Hence, first, I would introduce another column in the table and calculate the ratio. Assuming we call the column ratio_average

to get values for our column simply take total_score / average_time_taken

so now when fetching our results from the table we'd only have to do the following:

TotalScore::orderBy('ratio_average', 'desc')->get();

Above will now give you the results in the correct order of positions from the first position

Answer 2

This is what a MySQL query would look like :

SELECT 
    (
      SELECT COUNT(*)
      FROM TableScore X
      WHERE X.ts > T.ts OR (X.ts = T.ts AND X.avg_times_taken < T.avg_times_taken)
    ) + 1 AS position   
FROM TableScore T      
WHERE T.user_id = '7';

WORKING DB-FIDDLE EXAMPLE HERE