如何使用python连接不同列表中的两个项目？

Question

How can I concatenate two items from different lists, together, if I have lists like this:

data_list = [['Toys', 'Communications', 'Leather'], ['Teddy', 'Mobile', 'Hand'], ['bear', 'phone', 'bag']]

I have used zip function to convert them into tuples like this:

data_tupled_list = zip(*data_list)

which results like this:

[('Toys', 'Teddy', 'bear'),
 ('Communications', 'Mobile', 'phone'),
 ('Leather', 'Hand', 'bag')]

I want a list like this:

[('Toys', 'Teddybear'),
 ('Communications', 'Mobilephone'),
 ('Leather', 'Handbag')]

Answer 1

You're most of the way there:

data_tupled_list = [(x[0],x[1]+x[2]) for x in zip(*data_list)]

It might be a little more pretty if you unpack the tuple:

data_tupled_list = [(a,b+c) for a,b,c in zip(*data_list)]

And it would definitely be prettier if you could give a , b and c more meaningful names.

Answer 2

There is a nice way to write this in Python3

>>> data_list = [['Toys', 'Communications', 'Leather'], ['Teddy', 'Mobile', 'Hand'], ['bear', 'phone', 'bag']]
>>> [(x, ''.join(args)) for x, *args in zip(*data_list)]
[('Toys', 'Teddybear'), ('Communications', 'Mobilephone'), ('Leather', 'Handbag')]

Answer 3

I'd operate on it in two parts; you really want to do the following:

data_list = [['Toys', 'Communications', 'Leather'], ['Teddy', 'Mobile', 'Hand'], ['bear', 'phone', 'bag']]
groups = data_list[0]
predicates = data_list[1]
suffixes = data_list[2]

combined = [ ''.join((pred, suff)) for pred, suff in zip(predicates, suffixes)]
finalresult = zip(groups, combined)