如何用R绘制3D矩阵的3D曲面

Question

I have 3D matrix of floating point numbers and I would like to produce a smoothed 3D surface of this matrix using R. Any suggestions are welcome. Thanks

Now I am using scatterplot3d ... But this function did not produce a smoothed surface

x<-read.table("/Users/me/Desktop/data.txt")
scatterplot3d(x$V1, x$V2, x$V3, highlight.3d = TRUE, angle = 30, col.axis = "blue", col.grid = "lightblue", cex.axis = 1.3, cex.lab = 1.1, pch = 20)

Answer 1

If you are able to create a 2D matrix (x,y) with the value being the z-axis value you could use the following

persp

Here is an example from R Graph Gallery. persp example

Answer 2

require(misc3d)

a <- 2/5

wsqr <-  1 - a^2
w <- sqrt(wsqr)
denom <- function(a,w,u,v) a*((w*cosh(a*u))^2 + (a*sin(w*v))^2)

fx <- function(u,v) -u + (2*wsqr*cosh(a*u)*sinh(a*u)/denom(a,w,u,v))
fy <- function(u,v) 2*w*cosh(a*u)*(-(w*cos(v)*cos(w*v)) - (sin(v)*sin(w*v)))/denom(a,w,u,v)
fz = function(u,v) 2*w*cosh(a*u)*(-(w*sin(v)*cos(w*v)) + (cos(v)*sin(w*v)))/denom(a,w,u,v)


parametric3d(fx = fx, fy = fy, fz = fz, 
             umin = -17, 
             umax = 17, 
             vmin = -77, 
             vmax = 77, 
             n = 100,
             color = c("grey17","grey21","red4","darkred","red4","grey21","grey17"),
             engine = "rgl")

Answer 3

I think that mba.surf from the MBA package would be a good choice for the smoothing, and as larrydag above suggests, persp would be good to image it. The code below is from the help page for the mba.surf function (swap LIDAR for your 3 column dataframe):

data(LIDAR)
mba.int <- mba.surf(LIDAR, 300, 300, extend=TRUE)$xyz.est
# Two ways of imaging....
image(mba.int, xaxs="r", yaxs="r")
persp(mba.int, theta = 135, phi = 30, col = "green3", scale = FALSE,
  ltheta = -120, shade = 0.75, expand = 10, border = NA, box = FALSE)