Django自引用外键

Question

I'm kind of new to webapps and database stuff in general so this might be a dumb question. I want to make a model ("CategoryModel") with a field that points to the primary id of another instance of the model (its parent).

class CategoryModel(models.Model):
    parent = models.ForeignKey(CategoryModel)

How do I do this? Thanks!

Answer 1

You can pass in the name of a model as a string to ForeignKey and it will do the right thing.

So:

parent = models.ForeignKey("CategoryModel")

Or you can use the string "self"

parent = models.ForeignKey("self")

Answer 2

You can use the string 'self' to indicate a self-reference.

class CategoryModel(models.Model):
    parent = models.ForeignKey('self')

https://docs.djangoproject.com/en/dev/ref/models/fields/#foreignkey

Answer 3

You also to set null=True and blank=True

class CategoryModel(models.Model):
    parent = models.ForeignKey("self", on_delete=models.CASCADE, null=True, blank=True)

null=True , to allow in database
blank=True , to allow in form validation

Answer 4

https://books.agiliq.com/projects/django-orm-cookbook/en/latest/self_fk.html

class Employee(models.Model):
    manager = models.ForeignKey('self', on_delete=models.CASCADE)

OR

class Employee(models.Model):
    manager = models.ForeignKey("app.Employee", on_delete=models.CASCADE)

https://stackabuse.com/recursive-model-relationships-in-django/