从开始日期到结束日期循环播放

Question

I'd like to make a selection list of dates that a user could choose from. The date should start by the Current date today and ends 5 days after . I just don't know how to execute it inside a loop so I wouldn't change the date over and over again. Thanks. Please help.

Answer 1

<?php
    $today = date('d/m/y');
    for($i=0; $i<5; $i++) {
          $nextDay = date('m/d/y', time() + (86400*$i));
          //make something with your date
    }
?>

Do you mean something like this?

Answer 2

echo "<select name=\"date\">\n";
for($i=time();$i<time()+5*24*60*60;$i+=24*60*60) {
    $d = date('Y-m-d', $i);
    echo echo "<option value=\"$d\">$d</option>\n";
}
echo "</select>\n";

Answer 3

Quick and dirty way:

for ($i = 0; $i < 5; $i++){
    print date('Y-m-d', mktime(0, 0, 0, date('m'), date('d') + $i, date('Y')));
    print "\n";
}

Answer 4

You can use a UNIX timestamp to store the time and loop.

Use date('Ym-d', $timestamp) to generate a string of date.

Use strtotime($string) to convert a Ymd string to timestamp integer.

$now = time();
for($i = $now; $i < $now + 5*86400; $i=$i+86400)
{
    $Ymd = date('Y-m-d', $i);
    //do other things here.
}

Answer 5

You can use the php DateTime functions for this:

<?php

    $date = new DateTime();    // Without argument: now
    $interval = new Dateinterval("P1D"); // Period: 1 day
    for ($i = 0; $i <= 5; $i++) {
       echo $date->format("Y-m-d")."\n";
       $date->add($interval);
    }
?>