[英]Need help with looping through start-end date
I have an event calendar with start and end date like this: 我有一个包含开始和结束日期的活动日历,如下所示:
16.08.2010 12:00:00
- 21.08.2010 20:00:00
16.08.2010 12:00:00
: 21.08.2010 20:00:00
16.08.2010 20:00:00
- 21.08.2010 23:00:00
16.08.2010 20:00:00
: 21.08.2010 23:00:00
18.08.2010 17:00:00
- 18.08.2010 19:00:00
18.08.2010 17:00:00
: 18.08.2010 19:00:00
Whenever an event goes on for more than one day, I need to loop through each day. 每当活动持续一天以上时,我就需要遍历每一天。
I found this thread, and I thought is could help me: How to find the dates between two specified date? 我找到了这个帖子,我想可以帮到我: 如何找到两个指定日期之间的日期?
I can't use the solution for PHP 5.3, because my server run PHP 5.2. 我无法使用PHP 5.3的解决方案,因为我的服务器运行PHP 5.2。
The other solutions do not procude output. 其他解决方案不会产生输出。
This is what I try to do: 这是我尝试做的:
$events = $data['events'];
foreach($ev as $e) :
$startDate = date("Y-m-d",strtotime( $e->startTime ));
$endDate = date("Y-m-d",strtotime( $e->endTime ));
for($current = $startDate; $current <= $endDate; $current += 86400) {
echo '<div>'.$current.' - '.$endDate.' - '.$e->name.'</div>';
}
endforeach;
In theory, this should loop through all days for an event that extends over several days. 从理论上讲,对于持续数天的事件,这应该贯穿整天。 But that's not happening. 但那并没有发生。
The logic is wrong somewhere.... please help :) 某个地方的逻辑是错误的。...请帮助:)
The problem is that you're trying to add numbers to a string. 问题是您要在字符串中添加数字。 date('Ym-d')
produces a string like 2011-01-31
. date('Ym-d')
产生类似2011-01-31
的字符串。 Adding numbers to it won't work [as expected]: '2011-01-31' + 86400 = ?
添加数字不会[按预期]: '2011-01-31' + 86400 = ?
. 。
Try something along these lines: 尝试以下方法:
// setting to end of final day to avoid glitches in end times
$endDate = strtotime(date('Y-m-d 23:59:59', strtotime($e->endTime)));
$current = strtotime($e->startTime);
while ($current <= $endDate) {
printf('<div>%s - %s - %s</div>', date('Y-m-d', $current), date('Y-m-d', $endDate), $e->name);
$current = strtotime('+1 day', $current);
}
The date("Ymd") is wrong, you need the strtotime Result in your for loop. 日期(“Ymd”)错误,您需要在for循环中使用strtotime结果。 Try this, it should work: 试试这个,它应该工作:
$events = array(
array('16.08.2010 12:00:00', '21.08.2010 20:00:00', 'event1'),
array('16.08.2010 20:00:00', '21.08.2010 23:00:00', 'event2'),
array('18.08.2010 17:00:00', '18.08.2010 19:00:00', 'event3'),
);
$dayLength = 86400;
foreach($events as $e) :
$startDate = strtotime( $e[0] );
$endDate = strtotime( $e[1] );
if(($startDate+$dayLength)>=$endDate) continue;
for($current = $startDate; $current <= $endDate; $current += $dayLength) {
echo '<div>'.date('Y-m-d', $current).' - '.date('Y-m-d', $endDate).' - '.$e[2].'</div>';
}
endforeach;
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.