[英]Count total of each activity type - oracle - sql
I have 3 activity types and need to display how many people have taken part in each event. 我有3种活动类型,需要显示每个活动有多少人参加。 So for example I need the query to display:
因此,例如,我需要查询来显示:
So far I have written the following query: 到目前为止,我已经编写了以下查询:
SELECT type_of_activity, COUNT (DISTINCT individual_id)
FROM activities, events, book_activity
WHERE activities.activity_code = events.activity_code
AND events.event_id = book_activity.event_id;
This is obviously wrong and comes up with the error " not a single group function
" 这显然是错误的,并出现错误“
not a single group function
”
What I need it to do is count each unique instances of individual ID where type - skiing for each type. 我需要做的是计算每个ID的每个唯一实例的类型-每个类型的滑雪。 I have looked at many resources but cannot find any examples or help
我看过很多资源,但找不到任何示例或帮助
SELECT a.type_of_activity, COUNT(ba.individual_id)
FROM BOOK_ACTIVITY ba
JOIN EVENTS e
ON e.event_id = ba.event_id
JOIN ACTIVITIES a
ON a.activity_code = e.activity_code
GROUP BY a.type_of_activity;
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.