Oracle SQL中每个GROUP的增量计数

Question

Consider below table :

IP Address
192.168.1.9
192.168.1.4
192.168.1.4
192.168.1.3
192.168.1.9

I want to write a sql query such that I get following data :

IP Address          Count
192.168.1.3           1
192.168.1.4           2
192.168.1.4           2
192.168.1.9           3
192.168.1.9           3

Answer 1

Use dense_rank() :

select ip_address, dense_rank() over (order by ip_address) as cnt
from t;

Answer 2

SELECT ip_address, 
ROW_NUMBER() OVER(PARTITION BY ip_address) AS count
FROM table1;

is what id do