正则表达式不匹配括号中的任何内容，只有字母，数字和空格，并且点后面没有任何内容

Question

For example, I have a filename [foo] FooBar[!].bar

How can I use regex to match FooBar but not [foo] , [!] or .bar

BTW, I'm using Python Regex, if that has any bearing.

Basically, I want to match anything that is not after a dot, or is not in brackets.

Answer 1

fileName = '[abc][def]Real Name[!].exe'
name = re.search('(\[[^]]*\])*([\w\s]+)', fileName).group(2)
print name

This should print 'Real Name'

Answer 2

(?:^|])(?!\.)([\w\s]+)(?:\[|$)'

这应该匹配由]和[或者开始和结束字符串并且前面没有点的任何单词+空格组合。

Answer 3

You could replace it all:

>>> re.sub(r'\[.*?\]|\..*', '', '[foo] FooBar[!].bar')
    ' FooBar'