在两个单词之间添加一个空格

Question

I have some words like "Light Purple" and "Dark Red" which are stored as "LightPurple" and "DarkRed". How do I check for the uppercase letters in the word like "LightPurple" and put a space in between the words "Light" and "Purple" to form the word "Light Purple".

thanks in advance for the help

Answer 1

You can use a regex to add a space wherever there is a lowercase letter next to an uppercase one.

Something like this:

"LightPurple".replace(/([a-z])([A-Z])/, '$1 $2')

UPDATE : If you have more than 2 words, then you'll need to use the g flag, to match them all.

"LightPurpleCar".replace(/([a-z])([A-Z])/g, '$1 $2')

UPDATE 2 : If are trying to split words like CSVFile , then you might need to use this regex instead:

"CSVFilesAreCool".replace(/([a-zA-Z])([A-Z])([a-z])/g, '$1 $2$3')

Answer 2

Okay, sharing my experience. I have this implement in some other languages too it works superb. For you I just created a javascript version with an example so you try this:

var camelCase = "LightPurple";
var tmp = camelCase[0];
for (i = 1; i < camelCase.length; i++)
{
    var hasNextCap = false;
    var hasPrevCap = false;

    var charValue = camelCase.charCodeAt(i);
    if (charValue > 64 && charValue < 91)
    {
        if (camelCase.length > i + 1)
        {
            var next_charValue = camelCase.charCodeAt(i + 1);
            if (next_charValue > 64 && next_charValue < 91)
                hasNextCap = true;
        }

        if (i - 1 > -1)
        {
            var prev_charValue =  camelCase.charCodeAt(i - 1);
            if (prev_charValue > 64 && prev_charValue < 91)
                hasPrevCap = true;
        }


        if (i < camelCase.length-1 &&
            (!(hasNextCap && hasPrevCap || hasPrevCap)
            || (hasPrevCap && !hasNextCap)))
            tmp += " ";
    }
    tmp += camelCase[i];
}

Here is the demo .

Answer 3

You could compare each character to a string of uppercase letters.

function splitAtUpperCase(input){  
   var uppers = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";  
   //start at 1 because 0 is always uppercase
   for (var i=1; i<input.length; i++){
      if (uppers.indexOf(input.charAt(i)) != -1){
         //the uppercase letter is at i
         return [input.substring(0,i),input.substring(i,input.length)];
      }
   }
}

The output is an array with the first and second words.

Answer 4

I think this is definitely not the best way to solve this problem (from an optimization perspective). But it works :)

const createSpacesBetweenWords = (char, index) => {
  if (char === char.toUpperCase() && index > 0) {
    return ` ${char}`;
  }

  return char;
};

function formatString(string) {
  return string
    .split('')
    .map(createSpacesBetweenWords)
    .join('');
}

formatString('LightPurple'); //returns a new string where words are separated by spaces