比较两个字符串的字符并忽略单词之间的空格

Question

I have 2 strings that use the same letters but one of them contains empty spaces at the end and between words

const message = 'Hello javascript world ';
const message1 = 'Hello     javascript world              ' ;

i want to ignore these empty spaces from 2 strings to only compare strings by the rest of chars in order to get a boolean result equal to true when i do so message === message1

imo this need a regex

Answer 1

Yes, you can use str.replace(/\s+/g, '') to remove the spaces then simply compare the strings
That would look something like this:

const message = 'Hello javascript world ';
const message1 = 'Hello     javascript world              ' ;

const equal = message.replace(/\s+/g, '') == message1.replace(/\s+/g, '');
// true

Answer 2

You can create a function utilizing the String.replaceAll() method like so:

const message = 'Hello javascript world ';
const message1 = 'Hello     javascript world              ' ;


const stringsMatch = (str1, str2) =>  str1.replaceAll(' ', '') == str2.replaceAll(' ', '')

console.log(stringsMatch(message, message1))

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Alternatively, you can use String.replace() method with regex like you mentioned

const stringsMatchRegex = (str1, str2) =>  str1.replace(/ /g, '') == str2.replace(/ /g, '')


console.log(stringsMatchRegex(message, message1))

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I would suggest also using String.toLowerCase() on both strings to bypass character case:

const stringsMatch = (str1, str2) =>  str1.replaceAll(' ', '').toLowerCase() == str2.replaceAll(' ', '').toLowerCase()