菜单驱动的Shell脚本重击

Question

As a complete novice to this i am trying to make a Shell Script. This will be driven by a menu with options such as delete file. The part i am scuppered by is for example, when the menu is up, how to get from pressing '1', to actually creating a new file (as this is option 1 on my menu) I appreciate this may not be the easiest of questions to understand as my use of technical terms is limited, however i would appreciate any help. Below is an example of the first section of my menu. I feel once i know where to start i'll be fine Menu

[1] Create File
[2] Delete File
[3] Rename file

Answer 1

Try doing this for example :

select x in "Create File" "Delete File" "Rename file"; do
    echo "$x choosen"
    break
done

Sample output

1) Create File
2) Delete File
3) Rename file
> 

Search select in the conditional construct paragraph here

Going further

To run some specific tasks with the result of the $x variable, you can use the case statement (like switch in other languages) like this :

case $x in
    Create*) touch file.txt ;;
    Delete*) rm -f file.txt ;;
    Rename*) mv file.txt file_old.txt ;;
esac

Answer 2

You can do it using switch/case statement. Please have a look on the bash manual or look for similar examples on the Web. Just google "switch case shell example"

Good luck