在XSL中访问参数值

Question

I am trying to get the value of the parameter of template named as is Round from the following code but it returns me the blank, can anybody tell me that how to get value of parameter in template

<xsl:apply-templates select="//solution">
            <xsl:with-param name="isRound">N</xsl:with-param>
</xsl:apply-templates>

  <xsl:template match="solution">
    <xsl:param name="isRound" />
    <test>
      <xsl:value-of select="$isRound"/>
    </test>
  </xsl:template>

The Output of this is:

<test></test>

Answer 1

Actually this works. I try it as following. Adding other necessary things such as stylesheet root element.

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

    <xsl:template match="/root">
        <xsl:apply-templates select="//solution">
            <xsl:with-param name="isRound">N</xsl:with-param>
        </xsl:apply-templates>
    </xsl:template>

    <xsl:template match="solution">
        <xsl:param name="isRound" />
            <test>
                <xsl:value-of select="$isRound"/>
            </test>
    </xsl:template>
</xsl:stylesheet>

Input for example.

<root>
    <solution/>
</root>

Result

<?xml version="1.0"?>
<test>N</test>