[英]how to set a new value to variable or param in xsl
I need some help about xsl. 我需要一些关于xsl的帮助。 I have a date attribute in source xml and i need to know its previous value because i need categorized according to date. 我在源xml中有一个日期属性,我需要知道它以前的值,因为我需要根据日期进行分类。 here is the source xml. 这是源xml。
source xml: source xml:
<root>
<license id="a" expireDate="2010-02-01"/>
<license id="b" expireDate="2010-02-01"/>
<license id="c" expireDate="2010-02-01"/>
<license id="d" expireDate="2010-02-04"/>
<license id="e" expireDate="2010-02-04"/>
<license id="f" expireDate="2010-02-12"/>
<license id="g" expireDate="2010-02-12"/>
</root>
I need to transform this to 我需要将其转换为
<licenses>
<expDate value="2010-02-01">
<license>a</license>
<license>b</license>
<license>c</license>
</expDate>
<expDate value="2010-02-04">
<license>d</license>
<license>e</license>
</expDate>
<expDate value="2010-02-12">
<license>f</license>
<license>g</license>
</expDate>
</licenses>
Actually, i can transform source xml which have different format from the given one. 实际上,我可以转换源xml,它具有与给定格式不同的格式。 I have read some articles but could not find the way to do this. 我读过一些文章,却找不到办法。 How can I keep the previous date value and check if its different from current one. 如何保留上一个日期值并检查它是否与当前日期值不同。
Thanks 谢谢
You can't change the value of a variable in XSLT, but you don't need to. 您无法在XSLT中更改变量的值,但您不需要。 The following stylesheet: 以下样式表:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:key name="byDate" match="license" use="@expireDate" />
<xsl:template match="/">
<licenses>
<xsl:apply-templates />
</licenses>
</xsl:template>
<xsl:template
match="license[generate-id() =
generate-id(key('byDate', @expireDate)[1])]">
<expDate value="{@expireDate}">
<xsl:apply-templates select="key('byDate', @expireDate)"
mode="group" />
</expDate>
</xsl:template>
<xsl:template match="license" mode="group">
<license>
<xsl:value-of select="@id" />
</license>
</xsl:template>
<xsl:template match="license" />
</xsl:stylesheet>
Applied to this input: 适用于此输入:
<root>
<license id="a" expireDate="2010-02-01"/>
<license id="b" expireDate="2010-02-01"/>
<license id="c" expireDate="2010-02-01"/>
<license id="d" expireDate="2010-02-04"/>
<license id="e" expireDate="2010-02-04"/>
<license id="f" expireDate="2010-02-12"/>
<license id="g" expireDate="2010-02-12"/>
</root>
Produces the following output: 产生以下输出:
<licenses>
<expDate value="2010-02-01">
<license>a</license>
<license>b</license>
<license>c</license>
</expDate>
<expDate value="2010-02-04">
<license>d</license>
<license>e</license>
</expDate>
<expDate value="2010-02-12">
<license>f</license>
<license>g</license>
</expDate>
</licenses>
Note: Your original XML was not well-formed. 注意:您的原始XML格式不正确。 I moved the license value to an id
attribute. 我将许可证值移动到id
属性。
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