批量重命名具有不同扩展名Linux Script的多个文件？

Question

I would like to write a linux script that will move or copy all files with the same filename (but different extensions) to a new filename for all those files, while maintaining their different extensions. In other words:

if I start with a directory listing:

file1.txt, file1.jpg, file1.doc, file12.txt, file12.jpg, file12.doc

I would like to write a script to change all the filenames without changing the extensions. For the same example, choosing file2 as the new filename the result would be:

file2.txt, file2.jpg and file2.doc, file12.txt, file12.jpg, file12.doc

So the files whose filename do not match the current criteria will not be changed.

Best wishes,

George

Answer 1

Note: If there's file1.doc in variable i , expression ${i##*.} extracts extension ie doc in this case.

---

One line solution:

for i in file1.*; do mv "$i" "file2.${i##*.}"; done

---

Script:

#!/bin/sh
# first argument    - basename of files to be moved
# second arguments  - basename of destination files
if [ $# -ne 2 ]; then
    echo "Two arguments required."
    exit;
fi

for i in $1.*; do
    if [ -e "$i" ]; then
        mv "$i" "$2.${i##*.}"
        echo "$i to $2.${i##*.}";
    fi
done

Answer 2

The util-linux-ng package (most of linux flavours have it installed by default) has the command 'rename'. See man rename for use instructions. Using it your task can be done simply as that

rename file1 file2 file1.*

Answer 3

To handle input files whose basenames contain special characters, I would modify plesiv's script to the following:

if [ $# -ne 2 ]; then
    echo "Two arguments required."
    exit;
fi

for i in "$1".*; do
    if [ -e "$i" ]; then
        mv "$i" "$2.${i##*.}"
        echo "$i to $2.${i##*.}";
    fi
done

Note the extra quotes around $1.