[英]Q&A: How do I figure out what the last day of the month is?
I was trying to write a roll-your-own timezone converter and I needed a way of determining what the last possible day of the month was.我正在尝试编写一个自己滚动的时区转换器,我需要一种方法来确定该月的最后一天是什么。 Upon some research, I discovered the formulas for finding a leap year.
经过一番研究,我发现了寻找闰年的公式。
It's a small contribution, but maybe I'll save someone else the 20 minutes it took me to figure out and apply it.这是一个很小的贡献,但也许我会节省其他人我花了 20 分钟弄清楚并应用它的时间。
This code accepts a signed short month, indexed at 0 (0 is January) and an int year that is indexed as 0 as well (2012 is 2012).此代码接受一个有符号的短月,索引为 0(0 是一月)和一个索引为 0 的 int 年(2012 年是 2012 年)。
It returns a 1 indexed day (the 27th is the 27th, but in SYSTEMTIME structures, etc., you usually need 0 indexed - just a head's up).它返回 1 索引日(27 日是 27 日,但在 SYSTEMTIME 结构等中,您通常需要 0 索引 - 只是抬头)。
short _get_max_day(short month, int year) {
if(month == 0 || month == 2 || month == 4 || month == 6 || month == 7 || month == 9 || month == 11)
return 31;
else if(month == 3 || month == 5 || month == 8 || month == 10)
return 30;
else {
if(year % 4 == 0) {
if(year % 100 == 0) {
if(year % 400 == 0)
return 29;
return 28;
}
return 29;
}
return 28;
}
}
What about 关于什么
#include <time.h>
#include <iostream>
int LastDay (int iMonth, int iYear)
{
struct tm when;
time_t lastday;
// Set up current month
when.tm_hour = 0;
when.tm_min = 0;
when.tm_sec = 0;
when.tm_mday = 1;
// Next month 0=Jan
if (iMonth == 12)
{
when.tm_mon = 0;
when.tm_year = iYear - 1900 + 1;
}
else
{
when.tm_mon = iMonth;
when.tm_year = iYear - 1900;
}
// Get the first day of the next month
lastday = mktime (&when);
// Subtract 1 day
lastday -= 86400;
// Convert back to date and time
when = *localtime (&lastday);
return when.tm_mday;
}
int _tmain(int argc, _TCHAR* argv[])
{
for (int m = 1; m <= 12; m++)
std::cout << "Last day of " << m << " is " << LastDay (m, 2002) << std::endl;
return 0;
}
It prints out (for year 2002)... 打印出来(2002年)......
Last day of 1 is 31
Last day of 2 is 28
Last day of 3 is 31
Last day of 4 is 30
Last day of 5 is 31
Last day of 6 is 30
Last day of 7 is 31
Last day of 8 is 31
Last day of 9 is 30
Last day of 10 is 31
Last day of 11 is 30
Last day of 12 is 31
I use a simple function that returns the whole date in the from of a (Standard) COleDateTime. 我使用一个简单的函数,它返回(标准)COleDateTime的整个日期。 It may not be as fast other options, but it is very effective, works for leap years and pretty fool proof.
它可能不是那么快的其他选择,但它非常有效,适用于闰年和非常简单的证明。
This is the Code that I am using: 这是我正在使用的代码:
COleDateTime get_last_day_of_month(UINT month, UINT year)
{
if(month == 2)
{ // if month is feb, take last day of March and then go back one day
COleDateTime date(year, 3, 1, 0, 0, 0); // 1 March for Year
date -= 1; // go back one day (the standard class will take leap years into account)
return date;
}
else if(month == 4 || month == 6 || month == 9 || month == 11) return COleDateTime(year, month, 30, 0, 0, 0);
else return COleDateTime(year, month, 31, 0, 0, 0);
}
import datetime
from datetime import date
from dateutil.relativedelta import relativedelta
year = int((date.today()).strftime("%Y"))
month = list(range(1, 13, 1))
YearMonthDay = [(datetime.datetime(year, x, 1) + relativedelta(day=31)).strftime("%Y%m%d") for x in month]
print(YearMonthDay)
['20220131', '20220228', '20220331', '20220430', '20220531', '20220630', '20220731', '20220831', '20220930', '20221031', '20221130', '20221231'] ['20220131', '20220228', '20220331', '20220430', '20220531', '20220630', '20220731', '20220831', '20220930', '20221031', '2021'
In C++20:在 C++20 中:
#include <chrono>
std::chrono::day
get_max_day(std::chrono::month m, std::chrono::year y)
{
return (y/m/std::chrono::last).day();
}
If you really need it with a type-unsafe API:如果你真的需要一个类型不安全的 API:
int
get_max_day(int m, int y)
{
return unsigned{(std::chrono::last/m/y).day()};
}
Word Year, Month, Day;
TDateTime datum_tdatetime = Date();
// first day of actual month
datum_tdatetime.DecodeDate(&year, &month, &day);
day = 1;
datum_tdatetime = EncodeDate(year, month, day);
// last day of previous month
datum_tdatetime -= 1;
// first day of previous month
datum_tdatetime.DecodeDate(&year, &month, &day);
day = 1;
datum_tdatetime = EncodeDate(year, month, day);
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