[英]Behaviour about const_cast<>
I have written a small problem for checking the behavior of const_cast on const data member. 我写了一个小问题来检查const数据成员上const_cast的行为。
using namespace std;
class myString{
public:
myString(char * str)
{
p=str;
}
const char * getString(){
return p;
}
private:
const char *p;
} ;
int main()
{
char *p=(char*)malloc(8);
cin>>p;
myString *m= new myString(p);
char *s =const_cast<char*>(m->getString());
s[6]='y';
cout<<s<<endl;
return 0;
}
After running this program I give the out as "yogendra" (a 8 letter string). 运行该程序后,我将其输出为“ yogendra”(8个字母的字符串)。 and i got the output as "yogendya" Now my doubt.
我得到的输出为“ yogendya”。现在我很怀疑。 Through const_cast<> we can override the behavior of the data member itself as here the string is const char* still after casting i can modify it.
通过const_cast <>,我们可以覆盖数据成员本身的行为,因为在转换后,字符串仍为const char *,我仍然可以对其进行修改。
You've described exactly what const_cast
is for - it allows you to removed the const
ness from something and modify it. 您已经准确地描述了
const_cast
的用途-它使您可以从某些内容中删除const
并进行修改。 It's up to you not to abuse that power. 您有责任不滥用这种权力。 :-)
:-)
(In your case this doesn't apply, but note that you can cause crashes by using const_cast
- for example: (在您的情况下,这并不适用,但是请注意,使用
const_cast
可能会导致崩溃-例如:
const char *c = "Hello";
char *s = const_cast<char*>(c);
s[0] = 'h';
could crash because the compiler can put the string literal into read-only memory.) 可能会崩溃,因为编译器可以将字符串文字放入只读内存中。)
yes, you can use const_cast<>
this way and it will not be an undefined behaviour since object pointed to by const char*
in your class is indeed non-const of type char*
. 是的,您可以以这种方式使用
const_cast<>
,并且不会出现未定义的行为,因为您的类中const char*
指向的对象确实是char*
类型的非const。 but be careful:. 不过要小心:。 C++ standard.
C ++标准。 §7.1.5.1/4 says
§7.1。5.1 / 4说
Except that any class member declared mutable (7.1.1) can be modified, any attempt to modify a const object during its lifetime (3.8) results in undefined behavior
除了可以声明任何声明为可变的类成员(7.1.1)之外,任何在其生存期(3.8)内修改const对象的尝试都会导致未定义的行为
safe use of const_cast is to ie cast const from const reference to a non-const object: when there is non const object and you have const ref to it, you can cast const from this safely 安全使用const_cast是将const从const引用转换为非const对象:当存在非const对象并且您具有const ref时,可以从此安全地转换const
If you say 如果你说
char *s =const_cast<char*>(m->getString());
then you essentially remove the "const" from the pointer, and you declare your s
to be a pointer to char, and it's a writable string. 然后从指针中删除“ const”,然后将
s
声明为指向char的指针,这是一个可写的字符串。 So the next line 所以下一行
s[6]='y';
is perfectly fine. 很好。 To keep the const you ought to declare
s
as a const pointer 要保留const,您应该将
s
声明为const指针
const char *s = m->getString();
in which case you won't be able to overwrite the constant string (error: assignment of read-only location). 在这种情况下,您将无法覆盖常量字符串(错误:分配只读位置)。 I assume that is what you want?
我以为那是你想要的? The
const_cast
will simply add/remove the const
and in your case, remove it. const_cast
将仅添加/删除const
,在您的情况下,将其删除。
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