如何计算列表中大于给定数字的元素的出现次数？

Question

Let's say I have this list:

a = [1.1, 2, 3.1, 4, 5, 6, 7.2, 8.5, 9.1]

I want to know how many elements are there bigger than 7. The result should be 3 . Is there an elegant way to do this in Python? I tried with count but it won't work.

Answer 1

>>> a = [1.1 , 2 , 3.1 , 4 , 5 , 6 , 7.2 , 8.5 , 9.1]
>>> sum(x > 7 for x in a)
3

This uses the fact that bool s are int s too.

_{(If you oppose this because you think it isn't clear or pythonic then read this link )}

Answer 2

更短，使用numpy：

sum(np.array(a)>7)

Answer 3

write a function that return you count of elements greater than specific number.

def get_max_count(l, num):
    count = 0

    for x in l:
        if x > num:
            count+=1
    return count

l = [1.1, 2, 3.1, 4, 5, 6, 7.2, 8.5, 9.1]
print get_max_count(l=l, num = 7)