MySQL右查询左连接图像表中的最新上传图像，并具有分页功能

Question

I'm trying to select few data from first table and only last uploaded image from images table. My tables look like this:

table named data_property has fields (columns):

property_id, timestamp, label_town, label_sub, property_name, price_night, description (and others which I don't need in this case).

And table images with fields (columns):

image_id, property_id and ext. Images name is image_id and ext is extension of images.

Every property (property_id row) have 12 images in images table. I need to join only last uploaded image per property and show 10 property ( $recordsize = 10 ) per page. I don't know how to organize my query

something like this:

SELECT 
    property_id, timestamp, label_town, label_sub, 
    property_name, price_night, description 
FROM 
    data_property 
    LEFT JOIN or INNER JOIN (image_id, property_id, ext 
ORDER BY image_id DESC LIMIT 1) 
    FROM images ORDER BY timestamp DESC LIMIT $recordstart, $recordsize

So, I need to select few field from data_property, join latest uploaded image which belong to that property, order by time of create property ad, sort from desc and show 10 property per page.

To get something like on this site: http://www.freehouseagent.com/property-for-sale/ireland/

Sorry for my bad English. I hope that you understand me. Thanks and Best regards!

Answer 1

try this:

SELECT 
    p.property_id, p.timestamp, p.label_town, p.label_sub,  p.property_name,
    p.price_night, p.description, i.image_id, i.property_id, i.ext 
FROM 
    data_property as p
LEFT JOIN images as i
ON p.property_id = i.property_id
GROUP BY p.property_id
ORDER BY p.timestamp DESC
LIMIT 10

---

you can also try this for more accuracy:

SELECT 
    p.property_id, p.timestamp, p.label_town, p.label_sub,  p.property_name,
    p.price_night, p.description, i.image_id, i.property_id, i.ext 
FROM 
    data_property as p
LEFT JOIN (
            SELECT MAX(image_id) as max, property_id
            FROM
                images
            GROUP BY
                property_id
           ) as n
ON p.property_id = n.property_id
LEFT JOIN
  images as i
ON i.image_id = n.max AND i.property_id = n.property_id
ORDER BY p.property_id DESC
LIMIT 10