用python打开带重音的xml文件

Question

I have this bit of code

for xmlword in moviexmlfind:
                    fileinfo = jukeboxpath + xmlword + "*.xml"
                    for name in glob.glob(fileinfo):

If an xmlword contains an accented letter it will error saying character not in range.

I have also tried:

if lookfor in open(lookfor + '.xml').read():

but that throws up encoding errors.

How can I code it to open accented file names?

Answer 1

import codecs
codecs.open("some/file/with/unicode","rb",encoding="utf8")

should work fine :) (assuming its utf8 encoding in the file)

also I think your problem is that you are just giving the filename without the path try os.path.join(jukeboxpath,xml_file_name) as your path instead of just xml_file_name