如何对方括号进行正则表达式？

Question

The problem: I want to get all of the square brackets' content, and then delete them, but only if the brackets are at the beginnig of the string.

For example, a given string [foo][asd][dsa] text text text will return array with all of the three brackets' content ( ["foo", "asd", "dsa"] ), and the string will become text text text .

But if the string looks like that: [foo] text [asd][dsa] text text , it'll take only the [foo] , and the string will become: text [asd][dsa] text text .

How can I do that using JavaScript?

Answer 1

The loop checks the start of the string for anything in square brackets, takes the contents of the brackets, and removes the whole lot from the start.

var haystack = "[foo][asd][dsa] text text text";
var needle = /^\[([^\]]+)\](.*)/;
var result = new Array();

while ( needle.test(haystack) ) {  /* while it starts with something in [] */
    result.push(needle.exec(haystack)[1]);       /* get the contents of [] */
    haystack = haystack.replace(needle, "$2"); /* remove [] from the start */
}

Answer 2

像var newstring = oldstring.replace(/\\[\\w{3}]/, "");

Answer 3

You could proceed using a while, taking the first, adding it to an array, remove it and then do all again. This would give this :

var t1 = "[foo][asd][dsa] text text text";
var rule = /^(?:\[([^\]]*)\])/g;
var arr = new Array();

while(m = rule.exec(t1)){
    arr.push(m[1]);
    t1 = t1.replace(rule, "")
}

alert(arr); // foo,asd,dsa
alert(t1);  //  text text text