如何使用正则表达式删除字符串中的方括号？

Question

['abc','xyz'] – this string I want turn into abc,xyz using regex in javascript. I want to replace both open close square bracket & single quote with empty string ie "" .

Answer 1

Use this regular expression to match square brackets or single quotes:

/[\[\]']+/g

Replace with the empty string.

 console.log("['abc','xyz']".replace(/[\\[\\]']+/g,''));

Answer 2

str.replace(/[[\\]]/g,'')

Answer 3

here you go

var str = "['abc',['def','ghi'],'jkl']";
//'[\'abc\',[\'def\',\'ghi\'],\'jkl\']'
str.replace(/[\[\]']/g,'' );
//'abc,def,ghi,jkl'

Answer 4

You probably don't even need string substitution for that. If your original string is JSON, try:

js> a="['abc','xyz']"
['abc','xyz']
js> eval(a).join(",")
abc,xyz

Be careful with eval , of course.

Answer 5

Just here to propose an alternative that I find more readable.

/\[|\]/g

JavaScript implementation:

let reg = /\[|\]/g

str.replace(reg,'')

As other people have shown, all you have to do is list the [ and ] characters, but because they are special characters you have to escape them with \\ .

I personally find the character group definition using [] to be confusing because it uses the same special character you're trying to replace.

Therefore using the | (OR) operator you can more easily distinguish the special characters in the regex from the literal characters being replaced.

Answer 6

This should work for you.

str.replace(/[[\]]/g, "");