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D3:在d3中查找地理多边形的区域

[英]D3: Finding the area of a geo polygon in d3

I've got a map that uses a geoJSON file to draw the countries. 我有一张地图使用geoJSON文件来绘制国家。 I then want to draw a circle centered on each country. 然后我想画一个以每个国家为中心的圆圈。 But for countries with several bounding regions (the US has mainland, Hawaii, Alaska) I want the circle on the largest bounding region. 但对于有几个边界地区的国家(美国有大陆,夏威夷,阿拉斯加),我希望这个圈子位于最大的边界地区。 I'm trying to do this by comparing the areas of the different bounding regions, but it isn't working for reasons I can't understand. 我试图通过比较不同边界区域的区域来做到这一点,但由于我无法理解的原因它无法正常工作。

Here's an example from the geoJSON, showing how Australia has multiple bounding regions: 以下是geoJSON的示例,显示了澳大利亚如何拥有多个边界区域:

{"type":"Feature","properties":{"name":"Australia"},"geometry":{"type":"MultiPolygon","coordinates":[[[[145.397978,-40.792549],[146.364121,-41.137695],[146.908584,-41.000546],[147.689259,-40.808258],[148.289068,-40.875438],[148.359865,-42.062445],[148.017301,-42.407024],[147.914052,-43.211522],[147.564564,-42.937689],[146.870343,-43.634597],[146.663327,-43.580854],[146.048378,-43.549745],[145.43193,-42.693776],[145.29509,-42.03361],[144.718071,-41.162552],[144.743755,-40.703975],[145.397978,-40.792549]]],[[[143.561811,-13.763656],[143.922099,-14.548311],[144.563714,-14.171176],[144.894908,-14.594458],[145.374724,-14.984976],[145.271991,-15.428205],[145.48526,-16.285672],[145.637033,-16.784918],[145.888904,-16.906926],[146.160309,-17.761655],[146.063674,-18.280073],[146.387478,-18.958274],[147.471082,-19.480723],[148.177602,-19.955939],[148.848414,-20.39121],[148.717465,-20.633469],[149.28942,-21.260511],[149.678337,-22.342512],[150.077382,-22.122784],[150.482939,-22.556142],[150.727265,-22.402405],[150.899554,-23.462237],[151.609175,-24.076256],[152.07354,-24.457887],[152.855197,-25.267501],[153.136162,-26.071173],[153.161949,-26.641319],[153.092909,-27.2603],[153.569469,-28.110067],[153.512108,-28.995077],[153.339095,-29.458202],[153.069241,-30.35024],[153.089602,-30.923642],[152.891578,-31.640446],[152.450002,-32.550003],[151.709117,-33.041342],[151.343972,-33.816023],[151.010555,-34.31036],[150.714139,-35.17346],[150.32822,-35.671879],[150.075212,-36.420206],[149.946124,-37.109052],[149.997284,-37.425261],[149.423882,-37.772681],[148.304622,-37.809061],[147.381733,-38.219217],[146.922123,-38.606532],[146.317922,-39.035757],[145.489652,-38.593768],[144.876976,-38.417448],[145.032212,-37.896188],[144.485682,-38.085324],[143.609974,-38.809465],[142.745427,-38.538268],[142.17833,-38.380034],[141.606582,-38.308514],[140.638579,-38.019333],[139.992158,-37.402936],[139.806588,-36.643603],[139.574148,-36.138362],[139.082808,-35.732754],[138.120748,-35.612296],[138.449462,-35.127261],[138.207564,-34.384723],[137.71917,-35.076825],[136.829406,-35.260535],[137.352371,-34.707339],[137.503886,-34.130268],[137.890116,-33.640479],[137.810328,-32.900007],[136.996837,-33.752771],[136.372069,-34.094766],[135.989043,-34.890118],[135.208213,-34.47867],[135.239218,-33.947953],[134.613417,-33.222778],[134.085904,-32.848072],[134.273903,-32.617234],[132.990777,-32.011224],[132.288081,-31.982647],[131.326331,-31.495803],[129.535794,-31.590423],[128.240938,-31.948489],[127.102867,-32.282267],[126.148714,-32.215966],[125.088623,-32.728751],[124.221648,-32.959487],[124.028947,-33.483847],[123.659667,-33.890179],[122.811036,-33.914467],[122.183064,-34.003402],[121.299191,-33.821036],[120.580268,-33.930177],[119.893695,-33.976065],[119.298899,-34.509366],[119.007341,-34.464149],[118.505718,-34.746819],[118.024972,-35.064733],[117.295507,-35.025459],[116.625109,-35.025097],[115.564347,-34.386428],[115.026809,-34.196517],[115.048616,-33.623425],[115.545123,-33.487258],[115.714674,-33.259572],[115.679379,-32.900369],[115.801645,-32.205062],[115.689611,-31.612437],[115.160909,-30.601594],[114.997043,-30.030725],[115.040038,-29.461095],[114.641974,-28.810231],[114.616498,-28.516399],[114.173579,-28.118077],[114.048884,-27.334765],[113.477498,-26.543134],[113.338953,-26.116545],[113.778358,-26.549025],[113.440962,-25.621278],[113.936901,-25.911235],[114.232852,-26.298446],[114.216161,-25.786281],[113.721255,-24.998939],[113.625344,-24.683971],[113.393523,-24.384764],[113.502044,-23.80635],[113.706993,-23.560215],[113.843418,-23.059987],[113.736552,-22.475475],[114.149756,-21.755881],[114.225307,-22.517488],[114.647762,-21.82952],[115.460167,-21.495173],[115.947373,-21.068688],[116.711615,-20.701682],[117.166316,-20.623599],[117.441545,-20.746899],[118.229559,-20.374208],[118.836085,-20.263311],[118.987807,-20.044203],[119.252494,-19.952942],[119.805225,-19.976506],[120.85622,-19.683708],[121.399856,-19.239756],[121.655138,-18.705318],[122.241665,-18.197649],[122.286624,-17.798603],[122.312772,-17.254967],[123.012574,-16.4052],[123.433789,-17.268558],[123.859345,-17.069035],[123.503242,-16.596506],[123.817073,-16.111316],[124.258287,-16.327944],[124.379726,-15.56706],[124.926153,-15.0751],[125.167275,-14.680396],[125.670087,-14.51007],[125.685796,-14.230656],[126.125149,-14.347341],[126.142823,-14.095987],[126.582589,-13.952791],[127.065867,-13.817968],[127.804633,-14.276906],[128.35969,-14.86917],[128.985543,-14.875991],[129.621473,-14.969784],[129.4096,-14.42067],[129.888641,-13.618703],[130.339466,-13.357376],[130.183506,-13.10752],[130.617795,-12.536392],[131.223495,-12.183649],[131.735091,-12.302453],[132.575298,-12.114041],[132.557212,-11.603012],[131.824698,-11.273782],[132.357224,-11.128519],[133.019561,-11.376411],[133.550846,-11.786515],[134.393068,-12.042365],[134.678632,-11.941183],[135.298491,-12.248606],[135.882693,-11.962267],[136.258381,-12.049342],[136.492475,-11.857209],[136.95162,-12.351959],[136.685125,-12.887223],[136.305407,-13.29123],[135.961758,-13.324509],[136.077617,-13.724278],[135.783836,-14.223989],[135.428664,-14.715432],[135.500184,-14.997741],[136.295175,-15.550265],[137.06536,-15.870762],[137.580471,-16.215082],[138.303217,-16.807604],[138.585164,-16.806622],[139.108543,-17.062679],[139.260575,-17.371601],[140.215245,-17.710805],[140.875463,-17.369069],[141.07111,-16.832047],[141.274095,-16.38887],[141.398222,-15.840532],[141.702183,-15.044921],[141.56338,-14.561333],[141.63552,-14.270395],[141.519869,-13.698078],[141.65092,-12.944688],[141.842691,-12.741548],[141.68699,-12.407614],[141.928629,-11.877466],[142.118488,-11.328042],[142.143706,-11.042737],[142.51526,-10.668186],[142.79731,-11.157355],[142.866763,-11.784707],[143.115947,-11.90563],[143.158632,-12.325656],[143.522124,-12.834358],[143.597158,-13.400422],[143.561811,-13.763656]]]]},"id":"AUS"},

And here's the code where I try to compare areas of different bounding regions. 这是我尝试比较不同边界区域的代码。 In that if statement, I'm trying to figure out if the country has more than one bounding region (that seems to work) and then in the for block, pick the largest one. if语句中,我试图弄清楚该国是否有多个边界区域(似乎有效),然后在for区块中选择最大的一个。

The problem: The "area" values I'm getting are all 0 and coords is always being chosen from the first bounding region, rather than the largest. 问题:我得到的“区域”值都是0,并且始终从第一个边界区域中选择coords ,而不是最大的。

function calculateCountryCenter(country) {

    var coords;

    //Check if the country has more than one bounding region.
    if (country.geometry.coordinates.length > 1) {

        coords = country.geometry.coordinates[0][0];

        var regionArea = path.area(country.geometry.coordinates[0]);

        for (var i=0; i<country.geometry.coordinates.length; i++) {
            if (path.area(country.geometry.coordinates[i]) > regionArea) {

                coords = country.geometry.coordinates[i][0];
            }
        }     

    } else {    
        coords = country.geometry.coordinates[0];
    }

    var averageCoords = [0,0];
    coords.forEach(function(coord) {
        averageCoords[0] += coord[0]
        averageCoords[1] += coord[1]
    });

    averageCoords[0] = averageCoords[0] / coords.length
    averageCoords[1] = averageCoords[1] / coords.length
    return averageCoords;

}

Here's the definition of the path. 这是路径的定义。

      var path = d3.geo.path().projection(projection)

Any guidance would be much appreciated. 任何指导都将非常感谢。 Many thanks. 非常感谢。

You can calculate the area of an arbitrary polygon using the Shoelace algorithm . 您可以使用Shoelace算法计算任意多边形的面积。

function polygonArea(points) {
  var sum = 0.0;
  var length = points.length;
  if (length < 3) {
    return sum;
  }
  points.forEach(function(d1, i1) {
    i2 = (i1 + 1) % length;
    d2 = points[i2];
    sum += (d2[1] * d1[0]) - (d1[1] * d2[0]);
  });
  return sum / 2;
}

polygonArea([[0,0], [4,0], [4,3]]);  // 6

Be aware that counterclockwise polygons will have a positive area, and clockwise polygons will have a negative area. 请注意,逆时针多边形将具有正面积,顺时针多边形将具有负面积。 Self-intersecting polygons typically have both clockwise and counterclockwise regions so their area will cancel out. 自相交多边形通常具有顺时针和逆时针区域,因此它们的区域将抵消。

Just because nobody has added a fully implemented answer yet, I've decided to answer my own question. 仅仅因为没有人添加完全实现的答案,我决定回答我自己的问题。 Here's code that takes geoJSON, as specified in the original question, and returns the coordinates of the largest bounding region for countries with more than one bounding region. 这里的代码采用原始问题中指定的geoJSON,并返回具有多个边界区域的国家/地区的最大边界区域的坐标。 For countries with only one bounding region, it returns the coords of the one bounding region. 对于只有一个边界区域的国家,它返回一个边界区域的坐标。 (I had to modify the code a bit to make it a standalone method here, but I'm pretty sure it's error-free.) (我不得不稍微修改一下代码,使其成为一个独立的方法,但我很确定它没有错误。)

function getLargestBoundingRegion(country) {

var largestRegionCoords;
var path = d3.geo.path()

//Check if the country has more than one bounding region.
if (country.geometry.coordinates.length > 1) {

    var regionToReturn = {        
        "type": "Feature",
        "geometry": {
            "type": "Polygon", 
            "coordinates": country.geometry.coordinates[0]},            
        };

    for (var i=1; i<country.geometry.coordinates.length; i++) {

        var testRegion = {        
                    "type": "Feature",
                "geometry": {
                    "type": "Polygon", 
                    "coordinates": country.geometry.coordinates[i]},            
            };

        if (path.area(testRegion) > path.area(regionToReturn)) {
            regionToReturn = testRegion;    
            largestRegionCoords = country.geometry.coordinates[i][0];    
            }
        }

    } else {    
        largestRegionCoords = country.geometry.coordinates[0];
    }

return largestRegionCoords;

The path.area function expects a feature and doesn't work with just a list of coordinates. path.area函数需要一个功能,并且不能仅使用一个坐标列表。 The easiest way to make it work is probably to copy the original object, delete all the coordinates that you're not interested in and pass that to path.area . 使其工作的最简单方法可能是复制原始对象,删除您不感兴趣的所有坐标并将其传递给path.area The code would look something like 代码看起来像

for (var i=0; i<country.geometry.coordinates.length; i++) {
    var copy = JSON.parse(JSON.stringify(country));
    copy.geometry.coordinates = [copy.geometry.coordinates[i]];
    path.area(copy);
    ...
}

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