C中的“ | =”运算符是什么意思？

Question

How does this code work:

int a = 1;
int b = 10;

a |= b;

how the a |= b; works? Seems like |= is not an operator in C?

Answer 1

It works like the | + the = operator, in a similar way as += works.

It is equivalent as

a = a|b;

I suggest you to read this article about operators: http://en.wikipedia.org/wiki/Operators_in_C_and_C%2B%2B#Bitwise_operators Ans this one about bitwise operation http://en.wikipedia.org/wiki/Bitwise_operation

Answer 2

Following the pattern of, for example, += :

a |= b;
// Means the same thing as:
a = a | b;

That is, any bits that are set in either a or b shall be set in a , and those set in neither shall not be set in a .

Answer 3

That's the "bitwise or" equal. It follows in the pattern of the plus equal += , minus equal -= , etc.

a |= b; is the same as a = a | b; a = a | b;

Answer 4

The expression a |= b; is equivalent to the expression a = a | b; a = a | b; .

Answer 5

This is compound assignment operator. It has meaning:

a = a | b;

Answer 6

This is the same as

a = a | b;

The same way as += -= etc

Answer 7

Its the bitwise OR operator , and

a |= b;

Its the same thing as

a = a | b;