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这个“>> =”运算符在C中意味着什么?

[英]What does this “>>=” operator mean in C?

unsigned long set;
/*set is after modified*/
set >>= 1;

I found this in a kernel system call but I don't understand, how does it work? 我在内核系统调用中发现了这个,但我不明白,它是如何工作的?

The expression set >>= 1; 表达式set >>= 1; means set = set >> 1; 表示set = set >> 1; that is right shift bits of set by 1 (self assigned form of >> bitwise right shift operator check Bitwise Shift Operators ). 这是set1右移位(自动分配形式的>>按位右移运算符检查按位移位运算符 )。

Suppose if set is: 假设如果set为:

BIT NUMBER    31   n=27        m=17                 0
              ▼    ▼           ▼                    ▼
set =         0000 1111 1111 1110 0000 0000 0000 0000

Then after set >> = 1; 然后set >> = 1; variable set becomes: 变量set变为:

BIT NUMBER    31   n=26        m=16                 0
              ▼     ▼           ▼                   ▼
set =         0000 0111 1111 1111 0000 0000 0000 0000

Notice the bits number shifted. 请注意位数已移位。

Note a interesting point: Because set is unsigned long so this >> operation should be logical shift ( unsigned shift ) a logical shift does not preserve a number's sign bit. 注意一个有趣的观点:因为setunsigned long所以这个>>操作应该是逻辑移位无符号移位 ),逻辑移位不会保留数字的符号位。

Additionally, because you are shifting all bits to right (towards lower significant number) so one right shift is = divide number by two. 此外,因为您将所有位向右移动(向较低有效数字移动)所以右移是=将数字除以2。

check this code (just to demonstrate last point): 检查此代码 (仅用于演示最后一点):

int main(){
 unsigned long set = 268304384UL;
 set >>= 1;
 printf(" set :%lu \n", set);
 set = 268304384UL;
 set /= 2;
 printf(" set :%lu \n", set);
 return 1; 
}

And output: 并输出:

 set :134152192 
 set :134152192

(note: its doesn't means >> and / are both same) (注意:它不代表>>/都是一样的)

Similarly you have operator <<= for left shift, check other available Bitwise operators and Compound assignment operators , also check section: bit expressions and difference between: signed/arithmetic shift and unsigned shift . 类似地,您有左移位运算符<<= ,检查其他可用的按位运算符复合赋值运算符 ,还检查部分: 位表达式和之间的区别:有符号/算术移位和无符号移位

This "right-shift"s the value by one bit. 这个“右移”的价值是一位。 If you move all the bits of an integer to the right by 1 then you effectively "divide by 2" because binary is a base-2 numbering system. 如果将整数的所有位向右移动1,则有效地“除以2”,因为二进制是基数为2的编号系统。

Imagine you have the number 12 in binary: 想象一下你的二进制数是12:

1100 = 12 in binary
 110 =  6 in binary (1100 right-shifted)

Just like if you moved all of the digits in a base-10 number right by one you would be dividing by 10. 就像你将一个基数为10的数字中的所有数字一个一个地移动一样,你将除以10。

这会将位向右移1,相当于除以2.有关位移的更多信息,请参阅http://msdn.microsoft.com/en-us/library/f96c63ed(v=vs.80)。 ASPX

Every binary operator can be combined with = . 每个二元运算符都可以与=组合。 In all cases 在所有情况下

dest op= expression

is equivalent to 相当于

dest = dest op expression

(except if dest has any side effects, they only take place once). (如果dest有任何副作用,它们只发生一次)。

So this means that 所以这意味着

set>>=1;

is equivalent to: 相当于:

set = set >> 1;

Since >> is the binary right-shift operator, it means to shift the value in set right by 1 bit. 由于>>是二进制右移运算符,它意味着set右侧的值移位1位。

上面的命令执行右移一位。从此链接中查看 c中的位操作http://www.cprogramming.com/tutorial/bitwise_operators.html

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