如果语句不起作用，则使用简写返回

Question

I can't seem to understand why does this work: 我似乎无法理解为什么这样做：

if(n < i)
{
    functoin();
}
else
{
    return;
}

While this doesn't work: 虽然这不起作用：

(n < i) ? function() : return;

why does the shorthand if-statement doesn't work? 为什么速记if语句不起作用？

Answer 1

return can't be used in an expression. return不能在表达式中使用。 Maybe you can try, 也许你可以尝试，

return (n < i) ? function() : undefined;

But that's only if you have one thing to do for each condition. 但是，只有你对每种情况都有一件事要做。